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Give in the question line segment = 10
Ie √(x2-x1)^2 + (y2-y1)^2 = 10
We need to find the coordinator
Statement 1 y2-y1/x2-x1 = -3
Not sufficient to answer
Statement 2 a coordinate are 2 and 6 still not sufficient
Adding 1 and 2 we get
Y2-6/X2-2 = -3
Y2 -6 = -3x2 + 6
Y2 +3x2 = 12
Still we are not able. To get any value
so insufficient
Answer is e

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Statement 1: the slope of line segment AB is -3

It is not possible to find the coordinates of the midpoint of line segment AB because we do not know either the coordinate of point A or point B.

Hence Insufficient


Statement 2 : the coordinates of point A are (2,6)


Coordinates of point A are given but we do not know the slope of line segment AB.

Hence Insufficient


Combining Statement 1 and 2 :

Now use little bit of logic here. ( Gmat is all about Logic !!)

You have coordinates of point A and a slope, But you don't know whether point B will lie "down the line of slope" OR "up the line of the slope". Hence from the given information you can get 2 valid values of midpoint of line AB.(depending on the position of B)

Hence Insufficient.


Correct answer is Option E. Neither.

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Explanation:

Given: AB has a length of 10

To find: co-ordinates of midpoint of line segment AB

Point A(X1,Y1)
Point B(X2,Y2)
Mid points: (X1+X2)/2 ,(Y1+Y2)/2

Statement 1: the slope of line segment AB is -3

-3 = (Y2-Y1)/(X2-X1)

We don't know any cordinations value of point A & B

Not Sufficient

Statement 2: the coordinates of point A are (2,6)
X1=2; Y1=6
Length = 10
Length = √{(X2-X1)^2 + (Y2-Y1)^2}
By putting values of X1; Y1 and length we get below equation.
60 = (X2)^2 + (Y2)^2 - 4(X2) - 12(Y2) --- 1

Not possible to solve the above eqn as 2 variables.

Not Sufficient.

From Statement 1 & 2;
-3 = (Y2-Y1)/(X2-X1)
-3 = (Y2-6)/(X2-2)
12 = 3(X2) + (Y2)----2

From Eqn 1 & 2; we will get 2 values each for X2 & Y2.

So 2 mid point's.

As line segment can be drawn in any of the 2 direction from Point A. Also attaching graph image for reference.

Not Sufficient.

IMO-E

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IMG_20200828_153236_089.jpg
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IMO E

Given: Length of AB=10
Check: Coordinates of the midpoint of line segment AB?

If a line segment has end points coordinate as A (a,b) & B(c,d) then the midpoint of line segment AB is (a+c)/2, (b+d)/2
Length^2 = 10^2 = (a-c)^2 + (b-d)^2


(1) the slope of line segment AB is -3
Let Coordinate be A (a,b) & B(c,d)
A/Q, (d-b)/(c-a) = -3
d-b = -3(c-a)

(a-c)^2 + (b-d)^2=10^2
=> (a-c)^2 +9(a-c)^2 =10^2
=> 10 (a-c)^2 = 10^2
=> (a-c)^2 = 10
=> (a-c) = ± √ 10 & (b-d)= ∓ 3√ 10
But from this we can't find the values of coordinates.

Insufficient

(2) the coordinates of point A are (2,6)
A (a,b)= 2,6
(a-c)^2 + (b-d)^2=10^2
(2-c)^2 + (6-d)^2 =10^2
Since we have no constrains on c,d , multiple values of c,d are possible.

Insufficient

Together A & B
(a,b)= 2,6
(a-c) = ± √ 10 => c = 2 ∓ √ 10
(b-d)= ∓ 3√ 10 => d= 6 ± 3√ 10

Midpoint (a+c)/2, (b+d)/2 =(4 ∓ √ 10)/2, (12 ± 3√ 10)/2
Therefore two values possible.

Insufficient

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Quote:
In the rectangular coordinate plane, if line segment AB has a length of 10, what are the coordinates of the midpoint of line segment AB?

(1) the slope of line segment AB is -3
(2) the coordinates of point A are (2,6)

I will try to solve this problem by equation.
From the question, the length of line AB = 10. What are the coordinates of midpoint of line AB?
1) the slope of line segment AB is -3
So y = mx+c
Knowing m = -3; y = -3x+c
Therefore, the coordinates of point A and point B are many values.
Insufficient.

2) the coordinates of point A are (2,6)
Knowing A = (2,6), B can be many values that have the distance, which is 10.
Insufficient.

1)+2): y = -3x+c and point A = (2,6)
So the coordinates of point B can be two value.
As a result, the midpoint of line AB cannot be found.
Insufficient.

I choose E.

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In the rectangular coordinate plane, if line segment AB has a length of 10, what are the coordinates of the midpoint of line segment AB?

(1) the slope of line segment AB is -3
According to attached file;
We know the blue line with its slope is -3. Know nothing about pointA and pointB.
INSUFFICIENT.

(2) the coordinates of point A are (2,6)
We know that A (2,6), but still know nothing about pointB.
INSUFFICIENT.

Combine (1)&(2);
According to attached file;
pointB can locate upper or lower pointA, so the coordinates of the midpoint of line segment AB can locate upper or lower pointA too. 2 possible points.
INSUFFICIENT.

ANS E.

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100= (x2-x1)^2+(y2-y1)^2

Y2-y1= -3(x2-x1)

Using both ens

100= (x2-x1)^2+ 9(x2-x1)^2

10=x2-x1)^2


X1= (10)^1\2 +2


X1+x2)/2 = (10)^1\2 + 4)/2.


Similarly mid point of y2 and y1

My answer is c
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