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quynhtran2209
If \(3^{m + n} = 27\) and \(3^{m – n} = \frac{1}{3}\) then \(\frac{m}{n} =\)


(A) \(\frac{1}{5}\)

(B) \(\frac{1}{4}\)

(C) \(\frac{1}{2}\)

(D) 1

(E) 2

Source: GMAT Official Practice


\(3^{m+n}\)=\( 3^3\)
\(3^{m – n} = 3^{-1} \)

Therefore
m+n=3
m-n=-1

solving n=2 , m=1

Answer: m/n = 1/2
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If \(3^{m + n} = 27\) and \(3^{m – n} = \frac{1}{3}\) then \(\frac{m}{n} =\)


(A) \(\frac{1}{5}\)

(B) \(\frac{1}{4}\)

(C) \(\frac{1}{2}\)

(D) 1

(E) 2

Source: GMAT Official Practice

\(3^{m + n} = 27\)
But \(3^{3} = 27\)

therefore, m+n = 3


\(3^{m – n} = \frac{1}{3}\)
but \(3^{-1} = \frac{1}{3}\)

therefore, m-n = -1


Adding the two equations we get, m = 1 and then n = 2

i.e. \(\frac{m}{n} = \frac{1}{2}\)

Answer: Option C
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Bunuel: You may tag this as GMAT PREP questions as it is from GMAT Question Pack 1
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Bunuel: You may tag this as GMAT PREP questions as it is from GMAT Question Pack 1
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Added the tag. Thank you.
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\(3^{m + n} = 27\)
= \(3^{m + n} = 3^3\)
= m + n = 3

\(3^{m – n} = \frac{1}{3}\)
= \(3^{m – n} = 3^(-1)\)
= m-n = -1

m=1, n = 2
\(\frac{m}{n} =\frac{1}{2}\)
quynhtran2209
If \(3^{m + n} = 27\) and \(3^{m – n} = \frac{1}{3}\) then \(\frac{m}{n} =\)

(A) \(\frac{1}{5}\)

(B) \(\frac{1}{4}\)

(C) \(\frac{1}{2}\)

(D) 1

(E) 2

PS05884

Source: GMAT Official Practice
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