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If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is

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If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   26 Mar 2017, 16:14
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If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.
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C
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kris19
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   29 Mar 2017, 04:50
prob statement is: y is an odd number, and x^3*y^4=648
648 can be written as 2^3*3^4
s1: y is positive, but since y is not mentioned as an int, we can't know for sure the value of y, not sufficient
s2: x is an int, then y can be negative or positive, since power of y is 4, not sufficient

s1&s2: x is an int and y is positive, then for sure y is an int and y = 3, sufficient
ans: C
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   20 Aug 2020, 13:49
VeritasKarishma and Bunuel .

Help please!

I could not find any combinations other than y being 3 from first statement. So i think statement 1 is sufficient. Kindly explain . However OA is given as C in the post
Thanks
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   20 Aug 2020, 14:39
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brains wrote:
VeritasKarishma and Bunuel .

Help please!

I could not find any combinations other than y being 3 from first statement. So i think statement 1 is sufficient. Kindly explain . However OA is given as C in the post
Thanks


Hi brains

For statement 1 we can have the following cases

\(x=2, y=3\)

\(x=\sqrt[3]{648}, y=1\)

Note that we are not told in statement 1 that \(x\) must be an integer

Hope this helps

Posted from my mobile device
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   20 Aug 2020, 23:59
If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   21 Aug 2020, 00:07
TargetHEC wrote:
If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient


All integers including negative ones must be either even or odd.

Even - {......, -6, -4, -2, 0, 2, 4, 6, ....}

Odd - {....., -5, -3, -1, 1, 3, ....}

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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   21 Aug 2020, 00:16
firas92 wrote:
TargetHEC wrote:
If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient


All integers including negative ones must be either even or odd.

Even - {......, -6, -4, -2, 0, 2, 4, 6, ....}

Odd - {....., -5, -3, -1, 1, 3, ....}

Posted from my mobile device



Ok, thanks for clearing up the misunderstanding I had. C makes sense then
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   24 Aug 2020, 04:29
Expert Reply
firas92 wrote:
brains wrote:
VeritasKarishma and Bunuel .

Help please!

I could not find any combinations other than y being 3 from first statement. So i think statement 1 is sufficient. Kindly explain . However OA is given as C in the post
Thanks


Hi brains

For statement 1 we can have the following cases

\(x=2, y=3\)

\(x=\sqrt[3]{648}, y=1\)

Note that we are not told in statement 1 that \(x\) must be an integer

Hope this helps

Posted from my mobile device


Without statement 2, y can be 1 and x = cube root of 648
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink] New post   25 Jun 2023, 11:14
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Re: If y is an odd number and x3y4=648, y=? 1) y is positive. 2) x is [#permalink]
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