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Given: \(\frac{y^k}{y^{5k}} = y^m\) IMPORTANT: many people will mistakenly apply some exponent laws and conclude that -4k = m. HOWEVER, before we apply these exponent laws, we must be certain that the base does not equal 0, 1 or -1, in which case the exponent laws fly out the window.
Statement 1: m = 4 Let's TEST some values.
There are several values of y, k and m that satisfy statement 1. Here are two: Case a: y = 1, k = 1 and m = 4. Plugging this into our given equation, we get \(\frac{1^1}{1^5} = 1^4\), which works! In this case, k = 1
Case b: y = 1, k = 2 and m = 4. Plugging this into our given equation, we get \(\frac{1^2}{1^{10}} = 1^4\), which works! In this case, k = 2
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: y = 4 There are several values of x and y that satisfy statement 2. Here are two: Case a: y = 4, k = 1 and m = -4. Plugging this into our given equation, we get \(\frac{4^1}{4^5} = 4^{-4}\), which works! In this case, k = 1
Case b: y = 4, k = 2 and m = -8. Plugging this into our given equation, we get \(\frac{4^2}{4^{10}} = 4^{-8}\), which works! In this case, k = 2
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Since statement 2 tells us that y does NOT equal 0, 1 or -1, we can safely apply some exponent laws: Given: \(\frac{y^k}{y^{5k}} = y^m\) Simplify left side to get: \(y^{-4k} = y^m\) So, -4k = m Statement 1 tells us that m = 4 Plug this into our equation to get: -4k = 4. which means k must equal -1 Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Given: \(\frac{y^k}{y^{5k}} = y^m\) IMPORTANT: many people will mistakenly apply some exponent laws and conclude that -4k = m. HOWEVER, before we apply these exponent laws, we must be certain that the base does not equal 0, 1 or -1, in which case the exponent laws fly out the window.
Statement 1: m = 4 Let's TEST some values.
There are several values of y, k and m that satisfy statement 1. Here are two: Case a: y = 1, k = 1 and m = 4. Plugging this into our given equation, we get \(\frac{1^1}{1^5} = 1^4\), which works! In this case, k = 1
Case b: y = 1, k = 2 and m = 4. Plugging this into our given equation, we get \(\frac{1^2}{1^{10}} = 1^4\), which works! In this case, k = 2
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Hi...
I would differ on the coloured portion. The Q is telling us that the equality is True. So if you have y as 0, the equation becomes undefined and the very basis of the Q falls flat.. Similarly for other values. If I say - " if y/y =y, what is y? I CAN NOT take y as 0 What you have conveyed is surely TRUE of the Q asked :- " IS y^k/y^5k=y^m.. So value of m is sufficient to tell about value of k.
_________________
I would differ on the coloured portion. The Q is telling us that the equality is True. So if you have y as 0, the equation becomes undefined and the very basis of the Q falls flat.. Similarly for other values. If I say - " if y/y =y, what is y? I CAN NOT take y as 0 What you have conveyed is surely TRUE of the Q asked :- " IS y^k/y^5k=y^m.. So value of m is sufficient to tell about value of k.
The part about the base not equaling zero is a general comment. For example, if we know that 0^x = 0^3, we can't conclude that x = 3
I don't agree your comments in blue. All we know is that the equation must hold true. My counterexamples for statement 1 satisfy the equation AND yield different answers to the target question. So, statement 1 cannot be sufficient.
Given: \(\frac{y^k}{y^{5k}} = y^m\) IMPORTANT: many people will mistakenly apply some exponent laws and conclude that -4k = m. HOWEVER, before we apply these exponent laws, we must be certain that the base does not equal 0, 1 or -1, in which case the exponent laws fly out the window. Statement 1: m = 4 Let's TEST some values.
There are several values of y, k and m that satisfy statement 1. Here are two: Case a: y = 1, k = 1 and m = 4. Plugging this into our given equation, we get \(\frac{1^1}{1^5} = 1^4\), which works! In this case, k = 1
Case b: y = 1, k = 2 and m = 4. Plugging this into our given equation, we get \(\frac{1^2}{1^{10}} = 1^4\), which works! In this case, k = 2
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: y = 4 There are several values of x and y that satisfy statement 2. Here are two: Case a: y = 4, k = 1 and m = -4. Plugging this into our given equation, we get \(\frac{4^1}{4^5} = 4^{-4}\), which works! In this case, k = 1
Case b: y = 4, k = 2 and m = -8. Plugging this into our given equation, we get \(\frac{4^2}{4^{10}} = 4^{-8}\), which works! In this case, k = 2
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Since statement 2 tells us that y does NOT equal 0, 1 or -1, we can safely apply some exponent laws: Given: \(\frac{y^k}{y^{5k}} = y^m\) Simplify left side to get: \(y^{-4k} = y^m\) So, -4k = m Statement 1 tells us that m = 4 Plug this into our equation to get: -4k = 4. which means k must equal -1 Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer: [spoiler=]C[/spoiler
RELATED VIDEO
Wow Intereseting, GMATPrepNow, I think we forget these exceptions. Thanks for remind us!
_________________
I would differ on the coloured portion. The Q is telling us that the equality is True. So if you have y as 0, the equation becomes undefined and the very basis of the Q falls flat.. Similarly for other values. If I say - " if y/y =y, what is y? I CAN NOT take y as 0 What you have conveyed is surely TRUE of the Q asked :- " IS y^k/y^5k=y^m.. So value of m is sufficient to tell about value of k.
The part about the base not equaling zero is a general comment. For example, if we know that 0^x = 0^3, we can't conclude that x = 3
I don't agree your comments in blue. All we know is that the equation must hold true. My counterexamples for statement 1 satisfy the equation AND yield different answers to the target question. So, statement 1 cannot be sufficient.
Cheers, Brent
hi...
I do not have any doubt on the logic as I would surely use it when it would have said - IS ... = ...
I am sure I have seen few Qs earlier where the final equation boils down to something like \(y^2=y^k\).. so if someone tells me that - If \(y^2+3y - (2y+2) = y^k +y-2\), what is k? the equation boils down to \(y^2=y^k\).. here answer should be k=2 but the logic of y as 0, 1 or -1 will not give k as 2 I may have not come across the y as 0,1 etc in such situations, and it may actually be true and I may be wrong. so would request if you have come across such use in actuals, it will surely help many who would go through this thread
But if someone tells me - Is \(y^2+3y - (2y+2) = y^k +y-2......y^2=y^k\).. we cannot answer as all those values of 1, -1 or 0 come in.
_________________
I do not have any doubt on the logic as I would surely use it when it would have said - IS ... = ...
I am sure I have seen few Qs earlier where the final equation boils down to something like \(y^2=y^k\).. so if someone tells me that - If \(y^2+3y - (2y+2) = y^k +y-2\), what is k? the equation boils down to \(y^2=y^k\).. here answer should be k=2 but the logic of y as 0, 1 or -1 will not give k as 2 I may have not come across the y as 0,1 etc in such situations, and it may actually be true and I may be wrong. so would request if you have come across such use in actuals, it will surely help many who would go through this thread
But if someone tells me - Is \(y^2+3y - (2y+2) = y^k +y-2......y^2=y^k\).. we cannot answer as all those values of 1, -1 or 0 come in.
I'm not sure I understand what you mean by the "IS" distinction. The target question asks "What IS the value of k"
ASIDE: If the question were... What is the value of k? (1) 1^3 = 1^k ...would statement 1 be sufficient?
_________________
I'm not sure I understand what you mean by the "IS" distinction. The target question asks "What IS the value of k"
ASIDE: If the question were... What is the value of k? (1) 1^3 = 1^k ...would statement 1 be sufficient?
Hi...
i meant by "IS....=.." :- Is \(x^7=x^k\)? here I would surely check x for 0,1,-1 and other values
But if the Q says it - IF \(x^7+x^2+4x+4=x^k+(x+2)^2\), what is the value of k? this will boil down to \(x^7=x^k\) and we should get k as 7..
1^3=1^k is a different matter as it is giving base as 1, but if there is a variable as x above, I have not seen a Q claiming it to be insufficient and substituting x as 0,1, and -1 . as I said earlier, maybe I have not seen a Q, it could be that there are such Q in actuals. If so, it will help.
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Statement 1: Now here the base \(y\) is a variable and not a constant, hence WE CANNOT EQUATE THE POWERS
For e.g if we had \(5^{-4k}=5^m\), then there powers could be equated i.e. \(-4k=m\), hence by knowing the value of \(m\), we could know the value of \(k\)
But here if \(y=0\) or \(1\), then irrespective of the value of \(m\), \(k\) could take any value. For e.g \(1^{-8}=1^{100}\), so here \(m=100\) and \(k\) could be \(2\).
Hence Statement 1 is Insufficient
Statement 2: nothing mentioned about \(k\) or \(m\). Insufficient
Combining 1 & 2: we know the value of \(y\) & \(m\), hence value of \(k\) can be calculated. Sufficient
Option C
gmatclubot
If y^k/y^5k = m, what is k?
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23 Mar 2018, 11:47