iaratul
In a country, 65% of male citizen and 68% of female citizen are eligible to vote. What percentage of the voters voted during the election?
(1) 65% of eligible male citizens voted.
(2) 68% of eligible female citizens voted.
I tried to solve the question like this, and got C, however, the OA states that the answer is E:
Let there be 100 males and 100 females in total
So, there are 65 male voters and 68 female voters
there are 65 + 68 = 133 total voters
Statement 1 says: 65% of eligible male citizens voted, so the number would be 65 * 65/100 ~ 43
Statement 2 says: 68% of eligible female citizens voted, so the number would be 68 * 68/100 ~ 47
Total votes: 43 + 47 = 90
Total Voters: 133
So, percentage of voters voted = 90/133 ~ 68%
The point is, it's possible to calculate the percentage from the given information, however, the OA disagrees. Can someone tell me where I went wrong?
Thanks
In your example you took the ration of male to female to be 1:1, of you take another ration you'll get another final percentage. For example, try males = 100 and females = 200.
Algebraically, you'd have the following:
65% of male citizen are eligible to vote --> 0.65m are eligible to vote;
68% of female citizen are eligible to vote --> 0.68f are eligible to vote.
65% of eligible male citizens voted --> 0.65*(0.65m) voted;
68% of eligible female citizens voted --> 0.68*(0.68f) voted.
Therefore, (voted)/(total) = \(\frac{0.65^2*m+0.68^2*f}{f+m}\). We cannot get the numerical value of this fraction. Not sufficient.
Answer: E.
Hope it's clear.