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In nine independent trials, what is the probability that Outcome A [#permalink]
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18 Feb 2015, 04:51
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15% (low)
Question Stats:
72% (00:36) correct 28% (00:46) wrong based on 196 sessions
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In nine independent trials, what is the probability that Outcome A happens at least once?
(1) The probability that Outcome A does not happen even once in any of the nine trials is 0.026 (2) the probability of Outcome A resulting in a single trial is 1/3.
In nine independent trials, what is the probability that Outcome A [#permalink]
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18 Feb 2015, 07:27
1
1
Probability (Outcome A happens at least once)+probability(Outcome A does not happen even once)=1. Statement 1= Sufficient. statement 2= We know probability of A=1/3, p(A')=2/3 with these we can find out all the cases when A occurs at least once.sufficient.
Re: In nine independent trials, what is the probability that Outcome A [#permalink]
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18 Feb 2015, 07:53
1
Bunuel wrote:
In nine independent trials, what is the probability that Outcome A happens at least once?
(1) The probability that Outcome A does not happen even once in any of the nine trials is 0.026 (2) the probability of Outcome A resulting in a single trial is 1/3.
Kudos for a correct solution.
Probability of Favorable Outcome + Probability of Unfavorable Outcome = 1
i.e. Probability of Favorable Outcome = 1 - Probability of Unfavorable Outcome
i.e. probability that Outcome A happens at least once = 1 - Probability that Outcome A never happens
Statement 1: P (A never happens) = 0.026 i.e. P (A happens atleast once) = 1- 0.026 = 0.974 SUFFICIENT
Statement 2: probability of Outcome A resulting in a single trial is 1/3 i.e. probability of Outcome A Not happen in a single trial is 1-(1/3) = 2/3 i.e. Outcome A never happens in all 9 trials = (2/3)^9 = 0.026 i.e. P (A happens atleast once) = 1- 0.026 = 0.974 SUFFICIENT
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Re: In nine independent trials, what is the probability that Outcome A [#permalink]
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18 Feb 2015, 08:43
1
Here we go:
St1: The probability that Outcome A does not happen even once in any of the nine trials is 0.026
We have been asked the probability that Outcome A happens at least once.
This can be calculate ---> (1 - 0.026)
Hence St1 is sufficient
St2 : the probability of Outcome A resulting in a single trial is 1/3. We can also calculate the probability of Outcome A not resulting in a single trial : (1 - 1/3) = 2/3
So we can find easily calculate the probability that Outcome A happens at least once by using above information.
Re: In nine independent trials, what is the probability that Outcome A [#permalink]
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22 Feb 2015, 12:08
Bunuel wrote:
In nine independent trials, what is the probability that Outcome A happens at least once?
(1) The probability that Outcome A does not happen even once in any of the nine trials is 0.026 (2) the probability of Outcome A resulting in a single trial is 1/3.
We know there are nine trials. To figure out the probability that Outcome A happens at least once, we would need a way to figure out the probability of A, P(A).
Statement #1: this statement gives us the complement. The complement of (Outcome A happens at least once) is (Outcome A does not happen at all). Complementary probabilities have a sum of 1 — P(not K) = 1 – P(K). Therefore, using the complement rule, we could figure out that P(A happens at least once) = 1 – P(A doesn’t happen at all) = 1 – 0.026 = 0.974 This information allows us to answer the prompt question. This statement, alone and by itself, is sufficient.
Statement #2: this statement gives us P(A), which would allow us to calculate the probability that A happens at least once in nine trials. This statement, alone and by itself, is sufficient.
Re: In nine independent trials, what is the probability that Outcome A [#permalink]
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24 Feb 2015, 09:02
Ans Is D coz of the following Statement 1 is sufficient as this is giving us the case of when an event is not happening ...question asked is when the event happens atleast once i.e 1-(when the event does not happens). Statement 2 is sufficient cause as we know the probability of event happening so we can find when atleast once.
In nine independent trials, what is the probability that Outcome A happens at least once?
(1) The probability that Outcome A does not happen even once in any of the nine trials is 0.026 (2) the probability of Outcome A resulting in a single trial is 1/3.
For Statement 2: How can we link outcome of event A with independent events in question stem?
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In nine independent trials, what is the probability that Outcome A happens at least once?
(1) The probability that Outcome A does not happen even once in any of the nine trials is 0.026 (2) the probability of Outcome A resulting in a single trial is 1/3.
For Statement 2: How can we link outcome of event A with independent events in question stem?
Though it is long time, let me try to explain how 2nd one is giving ans. 1st one is obvious.
let say there are 3 balls in a pot A, B and C. and you need to select one(A) randomly. when it is asked at least one, that means you can be successful 9 times to any 1 time. but don't fail all 9 times. means One attempted 9 times and all those 9 times one selected B or C. So if we find the probability to fail every time. We can find the probability of at least one time. probability to fail one time is 2/3. so for failing 9 times will be \((2/3)^9\).
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72% (00:36) correct 
