Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
21 Jun 2017, 01:00
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:22) correct
20%
(01:40)
wrong
based on 64
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure, what is the area of Triangle ABC ?
(A) 25
(B) 50
(C) \(\frac{100}{\sqrt{2}}\)
(D) 100
(E) \(100\sqrt{2}\)
Attachment:
2017-06-21_1155.png [ 9.28 KiB | Viewed 4884 times ]
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
sashiim20
Joined: 04 Dec 2015
Last visit: 05 Jun 2024
Posts: 620
Own Kudos:
Given Kudos: 276
Location: India
Concentration: Technology, Strategy
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
WE:Information Technology (Consulting)
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
Posts: 620
Kudos:
1,682
21 Jun 2017, 01:34
Kudos
Bookmarks
Bunuel
In the figure, what is the area of Triangle ABC ?
(A) 25
(B) 50
(C) \(\frac{100}{\sqrt{2}}\)
(D) 100
(E) \(100\sqrt{2}\)
Attachment:
2017-06-21_1155.png
Given from the diagram \(\triangle\) ABC is isosceles triangle. Therefore \(\angle ABC = \angle ACB\).
AD is the height and median on BC. Hence, BD = DC. Given side \(AC = 10.\)
Given from the diagram \(\triangle\) ADC is isosceles right triangle (45:45:90 triangle). Therefore \(\angle DAC = \angle ACD\) \(= 45^{\circ}\) .
Sides of isosceles right triangle (45:45:90 triangle) are in ratio \(x : x : x \sqrt{2}\)
\(AD : DC : AC =\) \(x : x : x \sqrt{2}\) = \(x : x : 10\)
\(x \sqrt{2}\) \(= 10 ==> x = \frac{10}{\sqrt{2}}\)
Multiplying numerator and denominator by \(\sqrt{2}\) we get;
\(x =10\sqrt{2}/ 2 = 5\sqrt{2}\).
\(AD = BD = DC = 5\sqrt{2}\).
\(BC = 5\sqrt{2} + 5\sqrt{2}= 10\sqrt{2}\).
Area of \(\triangle ABC = 1/2 * base * height = 1/2 * BC * AD\)
Area of \(\triangle\) ABC = \(\frac{1}{2} * 10 \sqrt{2} * 5\sqrt{2}\).
Area of \(\triangle ABC = 5\sqrt{2} * 5\sqrt{2}\)
Area of \(\triangle ABC = 25 * 2 = 50\) . Answer (B) ...
21 Jun 2017, 01:49
Kudos
Bookmarks
In Triangle ABC, Since AB = AC = 10
We know that angles opposite to equal sides are equal. Therefore, Angle ABC = 45 Degree.
Since angles is any triangle total 180 Degree, Angle BAC = 180 - (45+45) = 90 Degree
Now triangle ABC(right angled at BAC) will have area which is given by formula :
\(\frac{1}{2}\) * AB(Base) * AC(Height) = \(\frac{1}{2}\) * 10 * 10 = \(\frac{100}{2}\) = 50(Option B)
We know that angles opposite to equal sides are equal. Therefore, Angle ABC = 45 Degree.
Since angles is any triangle total 180 Degree, Angle BAC = 180 - (45+45) = 90 Degree
Now triangle ABC(right angled at BAC) will have area which is given by formula :
\(\frac{1}{2}\) * AB(Base) * AC(Height) = \(\frac{1}{2}\) * 10 * 10 = \(\frac{100}{2}\) = 50(Option B)
