Last visit was: 14 Dec 2024, 20:23 It is currently 14 Dec 2024, 20:23
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
TARGET730
Joined: 10 Sep 2014
Last visit: 06 Aug 2021
Posts: 58
Own Kudos:
273
 []
Given Kudos: 102
Posts: 58
Kudos: 273
 []
1
Kudos
Add Kudos
15
Bookmarks
Bookmark this Post
User avatar
chetan2u
User avatar
RC & DI Moderator
Joined: 02 Aug 2009
Last visit: 14 Dec 2024
Posts: 11,433
Own Kudos:
38,047
 []
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert reply
Posts: 11,433
Kudos: 38,047
 []
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
jayanthjanardhan
Joined: 29 May 2013
Last visit: 17 Aug 2017
Posts: 84
Own Kudos:
Given Kudos: 42
Location: India
Concentration: Technology, Marketing
WE:Information Technology (Consulting)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
chetan2u
User avatar
RC & DI Moderator
Joined: 02 Aug 2009
Last visit: 14 Dec 2024
Posts: 11,433
Own Kudos:
38,047
 []
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert reply
Posts: 11,433
Kudos: 38,047
 []
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
jayanthjanardhan
Any solutions to the correct answer?

Hi ,
the correct answer is D and the solution given above is for D only but its a typo error and by mistake i have written it as C

firstly the Question tells us that RQ and PQ are perpendicular at Q..
Now the coordinates of the point R are (-h, -k), so R is at a distance of 2h from line x and at dist of 2k from line Y..
as line X bisect RQ .... length of RQ =4h and coord (3h,-k)..
as line Y bisect PQ .... length of PQ =4k and coord (3h,3k). ans D
User avatar
jayanthjanardhan
Joined: 29 May 2013
Last visit: 17 Aug 2017
Posts: 84
Own Kudos:
Given Kudos: 42
Location: India
Concentration: Technology, Marketing
WE:Information Technology (Consulting)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chetan, thanks for ur response. However, i am having tough time visualising the lines and the perpendicular bisectors. Is it possible for u to show it on the graph?
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,341
Own Kudos:
3,706
 []
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,341
Kudos: 3,706
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jayanthjanardhan
chetan, thanks for ur response. However, i am having tough time visualising the lines and the perpendicular bisectors. Is it possible for u to show it on the graph?

Assume that h >0 and k>0 (this assumption does not negate anything in the question stem!)

Now start with point R: This will lie in the 3rd Quadrant . The coordinates of this point are (-h,-k).

Follow, the information to calculate the coordinates for Q and then finally for P to get the correct answer. Make sure to remember that perpendicular bisectors bisect (or divide into 2 equal parts). Thus, OP = OQ and QT = TR in the attached figure.

Another way to look at this problem is to assume certain values of h and k and then do what the questions says. You will end up with the same answer.
Attachments

6-30-15 11-43-41 AM.jpg
6-30-15 11-43-41 AM.jpg [ 28.34 KiB | Viewed 6872 times ]

User avatar
chetan2u
User avatar
RC & DI Moderator
Joined: 02 Aug 2009
Last visit: 14 Dec 2024
Posts: 11,433
Own Kudos:
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert reply
Posts: 11,433
Kudos: 38,047
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jayanthjanardhan
chetan, thanks for ur response. However, i am having tough time visualising the lines and the perpendicular bisectors. Is it possible for u to show it on the graph?

Hi,
it has been correctly transformed on the graph above ..
User avatar
jayanthjanardhan
Joined: 29 May 2013
Last visit: 17 Aug 2017
Posts: 84
Own Kudos:
Given Kudos: 42
Location: India
Concentration: Technology, Marketing
WE:Information Technology (Consulting)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
awesome!...thanks a lot guys!
User avatar
SW4
Joined: 23 Sep 2016
Last visit: 05 Jul 2017
Posts: 87
Own Kudos:
Given Kudos: 8
Posts: 87
Kudos: 122
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In the xy-plane, the line y = k is the perpendicular bisector of the line segment PQ and the line x = h is the perpendicular bisector of the line segment RQ. If the coordinates of the point R are (-h, -k), then what are the coordinates of the point P?

A) (-5h, -5k)
B) (-3h, -3k)
C) (2h, 2k)
D) (3h, 3k)
E) (5h, 5k)
avatar
praneet87
Joined: 27 Aug 2014
Last visit: 03 Jun 2018
Posts: 43
Own Kudos:
Given Kudos: 6
Location: Canada
Concentration: Strategy, Technology
GMAT 1: 660 Q45 V35
GPA: 3.66
WE:Consulting (Consulting)
GMAT 1: 660 Q45 V35
Posts: 43
Kudos: 16
Kudos
Add Kudos
Bookmarks
Bookmark this Post
So I just used real values. A lot less confusing. Assumed that R has an x-coordinate of -2. So if 2 is bisecting QR and R has has an x coordinate of -2. So the x co-ordinate of Q should be 6. if h=2 then Q should be 3h. I quickly cross checked by having h=3 and my assumption checked out. If you look at the answer there only 1 option with the x co-ordinate as 3h since P will have the same co-ordinate.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 35,825
Own Kudos:
Posts: 35,825
Kudos: 930
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderator:
Math Expert
97877 posts