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TheUltimateWinner
Joined: 23 Feb 2015
Last visit: 16 Apr 2026
Posts: 2,465
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Schools: Harvard '24 Judge '23 LBS '24 McCombs '24 Mendoza Tepper '24 Ross '24 Cox Marshall '24 Fisher Kelley '24 Jones McDonough '24 Owen '24 Terry BU Simon '24 Katz GWU Mason Babson Gabelli Foster '24 Goizueta '24 Scheller Stern '23 CBS '23 Booth '23 Haas '25 Wharton '25 Stanford '26 Johnson'23 Fuqua '23 Kellogg '23 Kenan-Flagler'23 INSEAD Aug 22 intake Olin '23 Said '23 Sloan '23 Carey Arizona "22 Yale '23 UC Davis Madison '23 Anderson '23 Carroll Carlson '23 Darden '23
Posts: 2,465
16 Apr 2019, 09:25
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:50) correct
33%
(01:32)
wrong
based on 54
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(x<5?\)
1) 7,9 and x form sides of an obtuse angled triangle
2) 4,5 and x form sides of a scalene triangle
1) 7,9 and x form sides of an obtuse angled triangle
2) 4,5 and x form sides of a scalene triangle
16 Apr 2019, 20:09
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AsadAbu
The concept that can be used is the Pythagorean theorem.
If it is 90, the sum of square of two sides is equal to square of third side.. \(a^2+b^2=c^2\)
If it is obtuse angled, the sum of square of two smaller sides is less than square of third side.. \(a^2+b^2<c^2\)..
And in case of scalene triangle, it is \(a^2+b^2>c^2\)
1) 7,9 and x form sides of an obtuse angled triangle
Range of X... \(7^2+9^2<x^2...49+81<x^2...X>√130..X>11\).. so X can be 12,13..till 15.99( as it has to be less than 7+9) when x is the largest side.
OR . \(x^2+7^2<9^2...81-49>x^2...x<√32\).... So, x can be 3,4, 5 when it is the smallest side.
Insufficient
2) 4,5 and x form sides of a scalene triangle
Range of X... \(4^2+5^2>x^2...16+25>x^2...X<√41.......X<6.5\)..
OR . \(x^2+4^2>5^2...x^2>25-16......x>3\).... So, 3<X<√41
Insufficient
Combined..
x can be in the range 3<x<√32....
So, x can be <5, but it can be greater than 5 when √25<x<√32..
Insufficient
E
28 Nov 2022, 20:08
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Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
