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14 Mar 2022, 01:30
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
68% (02:04) correct
32%
(02:18)
wrong
based on 66
sessions
History
Date
Time
Result
Not Attempted Yet
Jack went up a hill to fetch a cylindrical pail of water. He filled the pail completely with 112π cubic centimeters of water, but then fell down, spilling half of the water out. At the bottom of the hill, Jack rested and discovered that the level of the remaining water was 3.5 cm below the top of the pail. What is the diameter of the circular base of the pail?
A. 3.0 cm
B. 4.0 cm
C. 4√2 cm
D. 8.0 cm
E. 8√2 cm
Are You Up For the Challenge: 700 Level Questions
A. 3.0 cm
B. 4.0 cm
C. 4√2 cm
D. 8.0 cm
E. 8√2 cm
Are You Up For the Challenge: 700 Level Questions
half = 3.5, therefore full = 7 = height
\(πr^2h = 112π\)
\(r^2*7 = 112\)
\(r^2 = 16\)
r = 4
Diameter = 2*4 = 8
Answer D
\(πr^2h = 112π\)
\(r^2*7 = 112\)
\(r^2 = 16\)
r = 4
Diameter = 2*4 = 8
Answer D
15 Mar 2022, 03:14
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I think this was an easy question.
formula
volume of cylinder- pie*r^2*h
solution
112pei= pie*r^2*h (pie gets cancelled)
112=r^2*h (now height is 7 cm since in the question remaining water was 3.5 cm)
112=r^2*7
16=r^2
therefore radius is 4.
answer
hence diameter is 8.
Ans is D. hope this helps!!
formula
volume of cylinder- pie*r^2*h
solution
112pei= pie*r^2*h (pie gets cancelled)
112=r^2*h (now height is 7 cm since in the question remaining water was 3.5 cm)
112=r^2*7
16=r^2
therefore radius is 4.
answer
hence diameter is 8.
Ans is D. hope this helps!!
