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Another way is

Assume total distance=D

Time taken to travel p% of the trip = \(\frac{D*p}{100v}\)

Time taken to travel rest of the trip = \((1-\frac{p}{100})*(\frac{D}{0.8v})\)

Total time taken
\(= \frac{D*p}{100v} + (\frac{100-p}{100})(\frac{5D}{4v})\)

\(=\frac{4D*p}{400v }+ (\frac{500D-5D*p}{400v})\)

\(= \frac{500D-D*p}{400v}\)

Average speed = D/ (500D-D*p/400v) = \( \frac{400v }{ 500 - p}\)


sjuniv32
On her way to work, Angela traveled \(p\) percent of the total trip at an average speed of \(v\) miles per hour and the rest of the distance at an average speed that was one-fifth less than \(v\). In terms of \(p\) and \(v\), what was Angela’s average speed for the entire commute?

(A)\( \frac{400v }{ 500 - p}\)

(B)\( \frac{500v }{ 400 - p}\)

(C)\( \frac{500v }{ 500 - p}\)

(D) \(\frac{500v }{ 600 - p}\)

(E) \(\frac{600v }{ 500 - p}\)
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sjuniv32
On her way to work, Angela traveled \(p\) percent of the total trip at an average speed of \(v\) miles per hour and the rest of the distance at an average speed that was one-fifth less than \(v\). In terms of \(p\) and \(v\), what was Angela’s average speed for the entire commute?

(A)\( \frac{400v }{ 500 - p}\)

(B)\( \frac{500v }{ 400 - p}\)

(C)\( \frac{500v }{ 500 - p}\)

(D) \(\frac{500v }{ 600 - p}\)

(E) \(\frac{600v }{ 500 - p}\)


Substitution is a pretty safe way here.
Let p=20, and v =50mph.
So 20 at 50mph and 80 at 40mph.
Total time taken = \(\frac{20}{50}+\frac{80}{40}=2.4\)

Total distance =100 and time taken =2.4
Average speed = 100/2.4=1000/24=125/3

Check option for this value.
A. 400*50/(480)=5*50/6=125/3

A
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Took me 5 min to solve ! Alas !

I did it by assuming the value of total distance as 100 then solving !

5 min : bad huh

Posted from my mobile device
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Given: On her way to work, Angela traveled \(p\) percent of the total trip at an average speed of \(v\) miles per hour and the rest of the distance at an average speed that was one-fifth less than \(v\).

Asked: In terms of \(p\) and \(v\), what was Angela’s average speed for the entire commute?

Let the total distance be D

Time taken for Dp% distance = Dp%/v

Time taken to cover rest = D(100%-p%)/(4v/5) = D(125%-1.25p%)/v

Average speed = D/{Dp%/v + D(400%-5p%/4)/v} = v/{p% + 125% -1.25p%} = 100v / (125-.25p) = 400v/(500-p)

IMO A
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