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09 Jun 2020, 06:48
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C
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69% (02:03) correct
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Set P consists of 10 positive integers arranged in order of increasing magnitude. The difference between any two successive terms of the set is 4. If the two largest terms of the set are removed, what is the decrease in the average(arithmetic mean) of the set?
A. 0
B. 2
C. 4
D. 6
E. 8
A. 0
B. 2
C. 4
D. 6
E. 8
09 Jun 2020, 07:09
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Bunuel
Set P consists of 10 positive integers arranged in order of increasing magnitude. The difference between any two successive terms of the set is 4. If the two largest terms of the set are removed, what is the decrease in the average(arithmetic mean) of the set?
A. 0
B. 2
C. 4
D. 6
E. 8
A. 0
B. 2
C. 4
D. 6
E. 8
CONCEPT: In any Arithmetic Progression, \(Mean = Median = \frac{First+Last}{2}\)
Original Series is {4, 8, 12, 16, 20, 24, 28, 32, 36, 40} i.e. \(Mean = \frac{4+40}{2} = 22\)
New Series is {4, 8, 12, 16, 20, 24, 28, 32} i.e. \(Mean = \frac{4+32}{2} = 18\)
Decrease = 22-18 = 4
Answer: Option C
09 Jun 2020, 09:13
Kudos
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Bunuel
Set P consists of 10 positive integers arranged in order of increasing magnitude. The difference between any two successive terms of the set is 4. If the two largest terms of the set are removed, what is the decrease in the average(arithmetic mean) of the set?
A. 0
B. 2
C. 4
D. 6
E. 8
A. 0
B. 2
C. 4
D. 6
E. 8
alternate way
find sum of numbers ; n/2 * (2a+(n-1)*d)
series be 4,8,12......36,40
10/2 *(8+(7*4) ; 220 / 10 ; 22 is avg
now when last two number are removed
left with
8/2 *(8+28) ; 144 ; avg 144/8 ; 18
so ∆ in avg ; 22-18 ; 4
OPTION C
