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The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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13 Jul 2017, 22:54
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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14 Jul 2017, 00:58
Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. The total sum of 10 distinct odd integers is 550 (1) the largest integer is 65...not sufficient ( Longer WayMaking Sets is to write 55 ten times and then play with numbers) 65,63,61,59,57,55,51,49,47,43 Mean is 55 and Median is 56 65,63,61,59,57,53,51,49,47,45 Mean is 55 and Median is 55 (2) the smallest integer is 41.....not sufficient 41,43,45,47,53,57,63,65,67,69 Mean is 55 and Median is 55 41,43,45,47,55,57,61,65,67,69 Mean is 55 and Median is 56 ON combining 41,45,51,53,55,57,59,61,63,65 Mean is 55 and Median is 56 41,47,49,53,55,57,59,61,63,65 Mean is 55 and Median is 56 Hence C
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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14 Jul 2017, 06:48
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Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. 1) Largest Int = 65 Insufficient. Multiple values possible. 2) Smallest int = 41 Insufficient. Multiple values possible. 1+2) 41 < 8 odd integers < 65 mean = 55 The mean is closer to 65, and we've lost leverage in terms of going below 41, or above 65 => the only place where I can switch numbers around is near 41. So the median remains the same at 56. Below are the cases. Case 1  41,45,51,53,55,57,59,61,63,65 Case 2  41,47,49,53,55,57,59,61,63,65 Sufficient. Answer is C IMO. My questionI took around 3.05 minutes to solve this, and I feel it's way too long. Is there a shorter way to do this question? Is there something I missed i.e. a shortcut?
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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14 Jul 2017, 10:25
akshayk wrote: Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. 1) Largest Int = 65 Insufficient. Multiple values possible. 2) Smallest int = 41 Insufficient. Multiple values possible. 1+2) 41 < 8 odd integers < 65 mean = 55 The mean is closer to 65, and we've lost leverage in terms of going below 41, or above 65 => the only place where I can switch numbers around is near 41. S o the median remains the same at 56.Below are the cases. Case 1  41,45,51,53,55,57,59,61,63,65 Case 2  41,47,49,53,55,57,59,61,63,65 Sufficient. Answer is C IMO. My questionI took around 3.05 minutes to solve this, and I feel it's way too long. Is there a shorter way to do this question? Is there something I missed i.e. a shortcut? akshayk how do u say that mean remains at 56,,on what basis???



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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14 Jul 2017, 10:47
mohshu wrote: akshayk wrote: Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. 1) Largest Int = 65 Insufficient. Multiple values possible. 2) Smallest int = 41 Insufficient. Multiple values possible. 1+2) 41 < 8 odd integers < 65 mean = 55 The mean is closer to 65, and we've lost leverage in terms of going below 41, or above 65 => the only place where I can switch numbers around is near 41. S o the median remains the same at 56.Below are the cases. Case 1  41,45,51,53,55,57,59,61,63,65 Case 2  41,47,49,53,55,57,59,61,63,65 Sufficient. Answer is C IMO. My questionI took around 3.05 minutes to solve this, and I feel it's way too long. Is there a shorter way to do this question? Is there something I missed i.e. a shortcut? akshayk how do u say that mean remains at 56,,on what basis??? Case 1  41,45,51,53 ,55,57,59,61,63,65 Case 2  41,47,49,53, 55,57,59,61,63,65 The middle 2 numbers in both cases are 55 and 57 (55 + 57)/2 = 112/2 = 56 So the median is 56. I couldn't come up with another possibility after combining the 2 statements.
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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10 Aug 2017, 02:01
Bunuel can you please help us in solving this in a systematic approach



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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10 Aug 2017, 02:09
I really hope there is a fast way as compared to the case method that seems a longer method



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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18 Aug 2017, 20:42
Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. Hey Bunuel , I took the long road and evaluated the values. Is there an algebraic approach/ a more logical approach to this? It took me 4 minutes to do this! :(
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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18 Aug 2017, 21:16
Sum = AVG*number of terms (n) Sum of the sequence =10(first term +last term)/2 using the first term/ last term we can find the median using arithmetic progression Sent from my XT1706 using GMAT Club Forum mobile app



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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18 Aug 2017, 21:20
Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. Is this data sufficiency question Sent from my XT1706 using GMAT Club Forum mobile app



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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19 Aug 2017, 02:17
Jagdishvenkat wrote: Bunuel wrote: The average (arithmetic mean) of 10 distinct odd integers in a set is 55. What is the median of these 10 integers?
(1) The largest integer is 65. (2) The smallest integer is 41. Is this data sufficiency question Sent from my XT1706 using GMAT Club Forum mobile appYes, this is a data sufficiency question. Options for DS questions are always the same. The data sufficiency problem consists of a question and two statements, labeled (1) and (2), in which certain data are given. You have to decide whether the data given in the statements are sufficient for answering the question. Using the data given in the statements, plus your knowledge of mathematics and everyday facts (such as the number of days in July or the meaning of the word counterclockwise), you must indicate whether— A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked. C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked. D. EACH statement ALONE is sufficient to answer the question asked. E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed. I suggest you to go through the following posts: ALL YOU NEED FOR QUANT. Ultimate GMAT Quantitative MegathreadHope this helps.
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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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07 Sep 2017, 00:55
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Is there any shorter way to do it instead of writing all the possible numbers.



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Re: The average (arithmetic mean) of 10 distinct odd integers in a set is [#permalink]
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09 Nov 2017, 08:17
asthagupta wrote: Is there any shorter way to do it instead of writing all the possible numbers. Hi Bunuel, Can u please post the shortcut solution...thanks
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