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Bunuel
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This is a very good question. Thanks Bunuel At least I am able to brush up the concepts for SI and CI. :)

Simple Interest For First Year = Compound Interest For the First Year

Simple Interest for 2 Years \(= $ 180\)

Simple Interest Per Year \(= $\frac{180}{2}\) \(= $90\)

Considering the difference between the Compound interest and Simple Interest for the second year \(= $18\)

We know that the compound interest add \($18\) in the \($90\)amount of the first year. This can give us the interest rate

\(= \frac{18}{90} = \frac{6}{30}= \frac{1}{5} = 20%\)


Hence, Anwer is D
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Hi..

can someone explain why are we doing (18/90) ?? As 90 is the simple interest and 18 is the difference between the two interests ??
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SI for 1st year = CI for 1st year = \($90\).

Let CI for the 2nd year = \(x\).

So, \(x - 90 = 18\)

\(x = $108\).

\(90 + 20\%(90) = 108\), so Ans - D.
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anuj11
Hi..

can someone explain why are we doing (18/90) ?? As 90 is the simple interest and 18 is the difference between the two interests ??

Hi Anuj11,

We know SI is 180$ for 2yrs, making it 90$ for each year.

The difference b/w Simple and Compound interest starts from 2nd year.

Hence the interest amount of 2nd year[90$] is compounding, and the difference b/w SI and CI as per the stem is 18$. The question is asking 18$ difference is what % of the interest amount.

18 = (x/100)90
x = (1/5) = 20%

Hope it answers your doubt.
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Bunuel
The difference, after two years, between compound interest and simple interest on a certain sum of money invested at the same rate of interest, is $18. If the simple interest accumulated on the sum after two years is $180, what is the rate of interest at which the sum of money was invested?

(A) 36%
(B) 30%
(C) 25%
(D) 20%
(E) 10%

We'll use the underlying logic behind interest to create a simple equation, without bothering with variables.
This is a Logical approach.

The only difference between the compound and simple interest is that the compound interest was calculated twice - once at the end of the first year and once at the end of the second year.
So, the $18 difference must be due to the second year's interest earned from the first year's interest.
Since 2 years of simple interest is $180, one year is $90 so 90*rate = 18 meaning that our interest rate is 18/90 = 2/10 = 20%

(D) is our answer.

Note that understanding the underlying logic created an extremely simple calculation: 18 divided by (180/2), as opposed to something full of variables.
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If simple interest was 180$, that means simple interest must have been 90$ per year. So, the difference in 18$ must have ocurred due to the interest in interest, i.e. (90*x)/100 = 18, x = 20%.

IMO D.
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urvashis09

Can you please elaborate the explaination which you mentioned above.

I have on concern , $18 is for 2 year , how you can take $90*x/100 = $18
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vipulshahi
urvashis09

Can you please elaborate the explaination which you mentioned above.

I have on concern , $18 is for 2 year , how you can take $90*x/100 = $18

Sure, when you calculate simple interest and compound interest for any given amount, the interest for the first year remains the same. Example, you have 100$ on both SI and CI for 2 years @ 10%, for the first year both will earn an interest of 10$. But for the second year, SI will again earn 10$, but CI will earn 11$. Why? because now the amount for CI becomes the amount initially invested plus the interest earned i.e. 100$ + 10$ = 110$. Since the interest earned is not taken out but added in the principal amount invested for CI, the difference starts coming from second year onwards.

Hope that helps.
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Bunuel
The difference, after two years, between compound interest and simple interest on a certain sum of money invested at the same rate of interest, is $18. If the simple interest accumulated on the sum after two years is $180, what is the rate of interest at which the sum of money was invested?

(A) 36%
(B) 30%
(C) 25%
(D) 20%
(E) 10%

Let’s let P = the principal and r = the interest rate., We use the formula for simple interest: I = P x r x t and the compound interest formula (for annual compounding): I = P x [(1 + r)^t -1], and we have:

P x r x 2 = 180 (from the simple interest formula)

P x [(1 + r)^2 - 1] = 198 (from the compound interest formula for annual compounding

Dividing the first equation by the second equation, we have:

(r x 2)/[(1 + r)^2 - 1]= 180/198

198(r x 2) = 180[(1 + r)^2 - 1]

198(2r) = 180(1 + 2r + r^2 - 1)

396r = 360r + 180r^2

180r^2 - 36r = 0

36r(5r - 1) = 0

r = 0

or

5r - 1 = 0

r = 1/5

Since r can’t be 0, r = 1/5 = 20%.

Answer: D
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Hello,
Could you someone explain why above question doesn't mentioned the total amount of compound interest for 2 years?

If simple interest 90$ =compound interest 90$ .
It means 90+90=180 for first year.
If compound interest 108(90$x/100%=18$; 18+90)=90 simple interest.
It means 90+108=198 for the second year.

So totall sum of interest,as I understand, shall be 180+198= 378$ for two years.
Or did I miss something?

Posted from my mobile device
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Bunuel
The difference, after two years, between compound interest and simple interest on a certain sum of money invested at the same rate of interest, is $18. If the simple interest accumulated on the sum after two years is $180, what is the rate of interest at which the sum of money was invested?

(A) 36%
(B) 30%
(C) 25%
(D) 20%
(E) 10%

\(ar2=180…ar=90\)
\((a(1+r)^2-a)-ar2=18\)
\([ar+r(a+ar)]-ar2=18…[ar+ar+ar^2]-ar2=18…ar^2=18\)
\(ar=90…ar^2=18…90/r=18/r^2…90r^2=18r…r=18/90=1/5=0.2\)

Ans. (D)
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