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The length of a rectangle is 4 centimeters longer than the width

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Senior Manager
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The length of a rectangle is 4 centimeters longer than the width  [#permalink]

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New post 21 Feb 2017, 18:39
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A
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C
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The length of a rectangle is 4 centimeters longer than the width, and the perimeter is 96 centimeters. How many square centimeters are
there in the area of the rectangle?

A. 48
B. 396
C. 572
D. 1,760
E. 2,288
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Posts: 47
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Re: The length of a rectangle is 4 centimeters longer than the width  [#permalink]

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New post 21 Feb 2017, 20:50
Let the length of the rectangle be L and width be W

Perimeter of rectangle = 2(L+W)

Now 2(L+W)=96 => L+W = 48 ... equation 1

It is also given that the length is 4 centimeters longer than the width
So L=W+4 ... equation 2

Substituting the value of L in equation 1, we get

(W+4)+W=48 => 2W+4=48 => 2W=44 => W=22

Substituting the value of W in equation 2 , we get L=W+4=22+4=26

Area of the triangle = L*W=26*22=572

Answer C
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Re: The length of a rectangle is 4 centimeters longer than the width  [#permalink]

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New post 21 Feb 2017, 21:35
vikasp99 wrote:
The length of a rectangle is 4 centimeters longer than the width, and the perimeter is 96 centimeters. How many square centimeters are
there in the area of the rectangle?

A. 48
B. 396
C. 572
D. 1,760
E. 2,288


length of a rectangle is 4 centimeters longer than the width

the perimeter is 96 centimeters
i.e. 2(l+b)=96
i.e. (l+b)=48
so we need to think of two numbers separated by 4 which add up to 48 which is easy to think as hey will be 22 and 26

so Area = 22*26 = 572

Answer: Option C
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Re: The length of a rectangle is 4 centimeters longer than the width &nbs [#permalink] 21 Feb 2017, 21:35
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