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21 Feb 2017, 19:39
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The length of a rectangle is 4 centimeters longer than the width, and the perimeter is 96 centimeters. How many square centimeters are
there in the area of the rectangle?
A. 48
B. 396
C. 572
D. 1,760
E. 2,288
there in the area of the rectangle?
A. 48
B. 396
C. 572
D. 1,760
E. 2,288
21 Feb 2017, 21:50
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Let the length of the rectangle be L and width be W
Perimeter of rectangle = 2(L+W)
Now 2(L+W)=96 => L+W = 48 ... equation 1
It is also given that the length is 4 centimeters longer than the width
So L=W+4 ... equation 2
Substituting the value of L in equation 1, we get
(W+4)+W=48 => 2W+4=48 => 2W=44 => W=22
Substituting the value of W in equation 2 , we get L=W+4=22+4=26
Area of the triangle = L*W=26*22=572
Answer C
Perimeter of rectangle = 2(L+W)
Now 2(L+W)=96 => L+W = 48 ... equation 1
It is also given that the length is 4 centimeters longer than the width
So L=W+4 ... equation 2
Substituting the value of L in equation 1, we get
(W+4)+W=48 => 2W+4=48 => 2W=44 => W=22
Substituting the value of W in equation 2 , we get L=W+4=22+4=26
Area of the triangle = L*W=26*22=572
Answer C
21 Feb 2017, 22:35
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vikasp99
The length of a rectangle is 4 centimeters longer than the width, and the perimeter is 96 centimeters. How many square centimeters are
there in the area of the rectangle?
A. 48
B. 396
C. 572
D. 1,760
E. 2,288
there in the area of the rectangle?
A. 48
B. 396
C. 572
D. 1,760
E. 2,288
length of a rectangle is 4 centimeters longer than the width
the perimeter is 96 centimeters
i.e. 2(l+b)=96
i.e. (l+b)=48
so we need to think of two numbers separated by 4 which add up to 48 which is easy to think as hey will be 22 and 26
so Area = 22*26 = 572
Answer: Option C
