tonebeeze wrote:

I got the problem correct. I just want to make sure my algebra translations are on point. Can someone please walk me through the algebra? Thanks!

The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?

1. The increased price per share of stock X was equal to the original price per share of stock Y.

2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.

Stocks Data |

Stock Name | Price/Share(2005) | Increase/Decrease in Price | Reduced/Increased Price/Share(2010) |

X | x | 0.1x Increase | 1.1x (Increased Price) |

Y | y | 0.1y Decrease | 0.9y(Reduced Price) |

Table above shows the price of stock X and Y in 2005 and 2010(duration of time for the change is same). Rest of the fields are self-explanatory.

Q: The reduced price per share of stock Y was what percent of the original price per share of stock X?

\(0.9y=(\frac{WHAT}{100})*x\)

\(WHAT=(\frac{0.9*100y}{x})\)

\(WHAT=(\frac{90y}{x})\)

Rephrase:

Q: What is \(\frac{y}{x}\)?

1. The increased price per share of stock X was equal to the original price per share of stock Y.

\(1.1x=y\)

\(\frac{y}{x}=1.1\)

Sufficient.

2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.

\(0.1x=\frac{10}{11}*0.1y\)

\(\frac{y}{x}=\frac{11}{10}\)

\(\frac{y}{x}=1.1\)

Sufficient.

Ans: "D"

_________________

~fluke

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