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Bunuel
The product of x and y is a constant. If the value of x is increased by 50%, by what percentage must the value of y be decreased?

A. 50%
B. 40%
C. 33 1⁄3%
D. 25%
E. 12 1⁄2%

x*y = constt.

Let x = y = 100 in beginning

i.e. x*y = 100*100 = 10000

x (100) ---becomes---> 1.5x (150)


i.e. 150*New 'y' = 10000
i.e. New 'y' = 10000/150 = 66.66

i.e. y decreases from 100 to 66.66 i.e. Decrease of 33.33%

Answer: option C
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Let x be 4 and y be 6, therefore xy = 24

50% increase in X is 4 x1.5 = 6
To maintain the constant of 24, Y will need to reduce to 4
so to calculate the % decrease in y, we use New Value - Old Value / Old Value
% Decrease in Y = 4-6/6 => 2/6 => 1/3
Convert 1/3 to % => 33.3%
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Hi All,

This question is based on a 'math truism' that shows up most often in certain types of "Distance Formula" questions. Here's a link to a question that's based on the exact SAME idea:

john-would-have-reduced-the-time-it-took-him-to-drive-from-his-home-to-210670.html?hilit=truism

GMAT assassins aren't born, they're made,
Rich
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Bunuel
The product of x and y is a constant. If the value of x is increased by 50%, by what percentage must the value of y be decreased?

A. 50%
B. 40%
C. 33 1⁄3%
D. 25%
E. 12 1⁄2%

Let \(x = 10\) and \(y = 10\) and \(xy = 100\)

If \(x\) is increased by \(50\)% its value is \(15\)

So, The value of \(y\) is \(\frac{100}{15} = 6.67\)

So, The value of y must be decreased by 33 1⁄3% , Answer must be (C)
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The ans is C 33\(\frac{1}{3}\)
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Hello from the GMAT Club BumpBot!

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