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The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6

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The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 16 Jan 2017, 08:30
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The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27

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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 16 Jan 2017, 11:52
1
Bunuel wrote:
The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27



total distace covered =330+66=396foot = 396/5280 miles
time =6sec = 6/3600 hrs
speed = (396/5280)/(6/3600)
=45mph

Ans C
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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 16 Jan 2017, 23:16
rohit8865 wrote:
Bunuel wrote:
The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27



total distace covered =330+66=396foot = 396/5280 miles
time =6sec = 6/3600 hrs
speed = (396/5280)/(6/3600)
=45mph

Ans C


Can you please explain bit more ?? why did we need to add 66 to 330 ?
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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 17 Jan 2017, 00:08
sumanainampudi wrote:
rohit8865 wrote:
Bunuel wrote:
The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27



total distace covered =330+66=396foot = 396/5280 miles
time =6sec = 6/3600 hrs
speed = (396/5280)/(6/3600)
=45mph

Ans C


Can you please explain bit more ?? why did we need to add 66 to 330 ?


Because the truck covered the length of the tunnel plus the length of the truck itself in 6 seconds.

The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 17 Jan 2017, 06:26
1
Bunuel wrote:
The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27


66+330=396 feet moved / 6 seconds = 66 feet per second

66 X 60=3,960 feet per minute

3,960 X 60 = 237,600 feet per hour

237,600 / 5280 = 45 Miles per hour ( personally I would just do 235/5 see that its 47 and look for the closest answer since the answer choices aren't close)
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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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New post 18 Jan 2017, 09:16
1
Bunuel wrote:
The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 seconds after the front–most end of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27


Let’s find the distance traveled by the front-most end of the truck first. After traveling the 330- foot tunnel, the front-most end travels an extra 66 feet for the rear-most end to exit the tunnel. Thus, the truck travels 330 + 66 = 396 feet in 6 seconds.

Let’s now convert 396 feet to miles and 6 seconds to hours.

396 feet = 396/5280 miles

6 seconds = 6/3600 = 1/600 hours.

Thus, the speed of the truck is (396/5280)/(1/600) = (396 x 600)/5280 = 45 miles per hour.

Answer: C
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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6  [#permalink]

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Re: The rear–most end of a 66 foot truck exits a 330 foot tunnel exactly 6 &nbs [#permalink] 14 May 2018, 02:56
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