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Bunuel
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Bunuel
The sum of the ages, in years, for Jordan and Avery is x, and Avery is twice as old as Jordan. In terms of x, how old will Jordan be in x years?

A. 4x/3

B. 3x/2

C. 5x/3

D. 2x

E. 7x/3

Let Jordan's age be J and Avery's age A. Given ;
\(J + A = x\)
\(A = 2J\)
\(J + 2J = x ==> 3J = x ==> J = \frac{x}{3}\)

\(J + x = \frac{x}{3} + x ==> \frac{x + 3x}{3} = \frac{4x}{3}.\) Answer A.
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Bunuel
The sum of the ages, in years, for Jordan and Avery is x, and Avery is twice as old as Jordan. In terms of x, how old will Jordan be in x years?

A. 4x/3

B. 3x/2

C. 5x/3

D. 2x

E. 7x/3

We can let Jordan’s current age = j and Avery’s current age = a.

Since the sum of their ages in years is x:

j + a = x

Since Avery is twice as old as Jordan:

a = 2j

We can substitute 2j for a in the first equation:

j + 2j = x

3j = x

j = x/3

Since Jordan’s current age is x/3, she will be x/3 + x = x/3 + 3x/3 = 4x/3 years old in x years.

Answer: A
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