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The symphony sells two kinds of tickets: orchestra, for $40, and upper
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07 May 2015, 03:41
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The symphony sells two kinds of tickets: orchestra, for $40, and upper tiers, for $25. On a certain night, the symphony sells 90 tickets and gets $2625 in revenue from the sales. How many orchestra tickets did they sell? A. 25 B. 35 C. 45 D. 55 E. 65 Kudos for a correct solution.
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Re: The symphony sells two kinds of tickets: orchestra, for $40, and upper
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07 May 2015, 07:01
Let o = number of orchestra tickets Let u = number of upper tier tickets
We know that o + u = 90
> o * 40 + u * 25 = 2.625
> rephrase o + u = 90 to > o = 90  u and insert in the equation
(90  u) * 40 + u * 25 = 2.625 3600  40u + 25u = 2.625 3600  15u = 2.625 15u =  975 u = 65
90  65 = number of orchestra tickets = 25



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The symphony sells two kinds of tickets: orchestra, for $40, and upper
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07 May 2015, 07:04
Let orchestra tickets be: X Therefore upper tiers tickets will be: 90X
Now, the following equation can be made: 40X + 25(90X) = 2625 40X + 2250  25X = 2625 15X = 375
Solving this, we get X = 25
Answer: A



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The symphony sells two kinds of tickets: orchestra, for $40, and upper
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07 May 2015, 10:01
Bunuel wrote: The symphony sells two kinds of tickets: orchestra, for $40, and upper tiers, for $25. On a certain night, the symphony sells 90 tickets and gets $2625 in revenue from the sales. How many orchestra tickets did they sell?
A. 25 B. 35 C. 45 D. 55 E. 65
Kudos for a correct solution. O + U = 90 45O * 25U = 2625 Two equations, two variables, solving will give O = 25 Hence, Answer is A



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Re: The symphony sells two kinds of tickets: orchestra, for $40, and upper
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11 May 2015, 04:06
Bunuel wrote: The symphony sells two kinds of tickets: orchestra, for $40, and upper tiers, for $25. On a certain night, the symphony sells 90 tickets and gets $2625 in revenue from the sales. How many orchestra tickets did they sell?
A. 25 B. 35 C. 45 D. 55 E. 65
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Notice, in verbal form, this is a twoequationstwo variables problem. The two variables are x = the number of orchestra tickets, and y = the number of upper tier tickets. One equation we get is x + y = 90, for the total number of tickets sold. That’s one equation. If we sell x orchestra tickets, we get $40 for each, so we get 40x in total revenue from all of the orchestra tickets. Similarly, we get 25y in total revenue from all the upper tier tickets. Thus, the total revenue is 40x + 25y = 2625. That’s our second equation. The first equation is incredibly convenient to multiply. I would rather multiply by 40 than by 25, so I make the coefficients of x match. I’ll multiply the first equation by 40, and the second equation by –1. 40x + 40y = 3600 (40x  25y = 2625) _______________ 15y = 975 Now, at first blush, that might look like an ugly division problem awaiting us, 975 divided by 15. Let’s break it down a bit. I know 900/3 = 300, and 75/3 = 25, so if I divide both sides by 3, I get 5y = 975/3 = 325 Now, 100/5 = 20, so three times that is 300/5 = 60. Of course, 25/5 = 5, so y = 325/5 = 65 We want x, so x + (65) = 90 right x = 25, answer = A. BTW, if these steps totally elude you, remember you can always backsolve from the numerical answers as a backup strategy.
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Re: The symphony sells two kinds of tickets: orchestra, for $40, and upper
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11 May 2015, 07:14
We are given that A + B = 90 (A and B representing both ticket types), and that 40A + 25B = 2625. You may factor out 5 from the latter equation just to make the numbers easier to work with. It becomes 8A + 5B = 525. Since A + B = 90, then B= 90  A. We are solving for A so it is easier to write the equation in terms of A. 8A + 5 (90A) =525 8A + 450  5A= 525 3A=75 A=25




Re: The symphony sells two kinds of tickets: orchestra, for $40, and upper
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11 May 2015, 07:14






