Last visit was: 21 Apr 2026, 20:29 It is currently 21 Apr 2026, 20:29
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
   1   2   3   
605-655 (Medium)|   Word Problems|                                 
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 21 Apr 2026
Posts: 22,276
Own Kudos:
26,526
 [12]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,276
Kudos: 26,526
 [12]
Each year for 4 years, a farmer increased the number of trees in a 01 Feb 2017, 09:21
7
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752
Show more

This problem is testing us on exponential growth. We are given that the number of trees increased by ¼ each year. To determine the number of trees in a certain year, we multiply the number of trees from the previous year by 1.25, or 5/4. Let’s let x equal the number of trees at the beginning (of the first year) of the 4-year period.

Start of year 1 = x

End of year 1 = x(5/4)

End of year 2 = x(5/4)(5/4)

End of year 3 = x(5/4)(5/4)(5/4)

End of year 4 = x(5/4)(5/4)(5/4)(5/4) = (625/256)x

We are given that there were 6,250 trees at the end of year 4, so we can set up the following equation:

(625/256)x = 6,250

625x = 6,250(256)

x = 10(256) = 2,560

Thus, there were 2,560 trees at the beginning of the 4-year period.

Answer: D
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [1]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [1]
Each year for 4 years, a farmer increased the number of trees in a 02 Feb 2017, 04:58
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
muthappashivani
What's wrong if we add up 1/4 for each year. Please help me understand this in detail.

First year begin: x------------- ending 5x/4
2nd year begin: 5x/4----------ending 3x/2(5x/4+x/4)
3year begin: 3x/2--------------ending 7x/4
4 year begin : 7x/4-----------ending 2x
I dont get the answer and iam not understanding what is wrong with this approch ... please help
Show more

This is what the question says:

"Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year"

He increases the trees by 1/4 of the number in the preceding year. So in 3rd year, he increases the trees by a fourth of the number of trees in the 2nd year, not one fourth of those in the 1st year.
Hence, 2nd year end/3rd year beg, the number of trees will be 5x/4 + (1/4)*(5x/4)
and so on...
avatar
marif822
avatar
Joined: 28 Mar 2017
Last visit: 21 Jun 2017
Posts: 1
Own Kudos:
3
 [3]
Given Kudos: 3
Posts: 1
Kudos: 3
 [3]
Each year for 4 years, a farmer increased the number of trees in a 21 Apr 2017, 05:18
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
All the above responses have been around trying to solve this algebraically. But we can do plug and play with the answer choices. We know what the end result trees are and we know what the annual increase. Given that the annual increase is 1/4 --> we know that the answer choices must be a factor of 4. So (B) is eliminated automatically since its an odd number.

The rest of the answers choices with the exception of D are not factors of 4. so we can eliminate that way.

Now if we had two answers that were divisible by 4, then we can easily do another step and recalculate.

Personally I find this much easier then having to the algebra formula but both can be done under 2 min easily.
User avatar
AK92
User avatar
Joined: 24 May 2016
Last visit: 17 Jul 2017
Posts: 12
Own Kudos:
15
 [3]
Given Kudos: 163
Location: Germany
Concentration: International Business, General Management
Posts: 12
Kudos: 15
 [3]
Each year for 4 years, a farmer increased the number of trees in a 04 Jun 2017, 02:26
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Another approach would be test the answers:
Normally, starting with B or D, I have chosen D as it is a cleaner number.
Assuming the farmer had at the beginning 2,560 trees he will have one year later (2,560 *1,25) or calculate 1/4 of it and add it.
--> After 1 year: 3200 trees
--> 2. Year: 3200*1,25= 4000 trees
--> 3. Year: 4000*1,25= 5000 trees
--> 4. Year: 5000*1,25= 6250 trees - Bingo!
As we arrived to the desired value Answer D is correct! The hint was that after the first year the numbers cleaned up very nicely and the calculations involved less work.
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,441
 [2]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,441
 [2]
Each year for 4 years, a farmer increased the number of trees in a Updated on: 25 Apr 2022, 15:54
Originally posted by BrentGMATPrepNow on 23 Jun 2018, 18:21.
Last edited by BrentGMATPrepNow on 25 Apr 2022, 15:54, edited 1 time in total.
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752
Show more

STRATEGY: Upon reading any GMAT Problem Solving question, we should always ask, Can I use the answer choices to my advantage?
In this case, we can test the answer choices. In fact, when I scan the answer choices, I see that 3 of them are automatically disqualified.
Now let's give ourselves up to 20 seconds to identify a faster approach.
In this case, we can also use algebra to solve the question.
Since I already know that I need to test just one answer choice, I'll go that route.

Let's first examine how I know that 3 answer choices are disqualified:
We’re told the number of trees increases by ¼ each year. Since answer choices A, B, and C aren’t divisible by 4, we can eliminate them immediately.
For example, check out what happens when we test choice C: 2250
If there were 2250 trees at the beginning, then the number of trees after 1 year = 2250 + (1/4 of 2250) = 2812.5, which makes no sense, since we can’t have half a tree.
Useful property: An integer is divisible by 4 if and only if the number created by its last two digits is divisible by 4.
Since 50 and 63 (the two-digit numbers created by the last two digits of A, B and C) aren’t divisible by 4, we can eliminate A, B and C.

This leaves us with D and E. From here, we’ll just test one option. If it works, we’re done. If it doesn’t work, the other option must be correct.
I’ll test choice D (2560), since calculating 1/4 of 2560 looks easier than calculating 1/4 of 2752:
- Number of trees at beginning = 2560
- Number of trees after 1 year = 2560 + (1/4 of 2560) = 2560 + 640 = 3200
Tip: We can calculate ¼ of k by dividing k by 2 twice
- Number of trees after 2 years = 3200 + (1/4 of 3200) = 3200 + 800 = 4000
- Number of trees after 3 years = 4000 + (1/4 of 4000) = 4000 + 1000 = 5000
- Number of trees after 4 years = 5000 + (1/4 of 5000) = 5000 + 1250 = 6250 Perfect!
Answer: E


Alternate approach
Important: if the number of trees increases by 1/4, then the new number is 5/4 times the original number.

Let x = the # of trees in the orchard at the beginning of the 4 year period.
(5/4)x = # of trees after 1 year
(5/4)(5/4)x = # of trees after 2 years
(5/4)(5/4)(5/4)x = # of trees after 3 years
(5/4)(5/4)(5/4)(5/4)x = # of trees after 4 years

We're told that, after 4 years, there are 6250 trees, so we now know that:
(5/4)(5/4)(5/4)(5/4)x = 6250
Simplify: (625/256)x = 6250
Multiply both sides by 256/625 to get: x = 6250(256/625)
Evaluate: x = 2560

Answer: D

Cheers,
Brent
avatar
yashna36
avatar
Joined: 18 Jul 2018
Last visit: 07 Apr 2019
Posts: 15
Own Kudos:
3
 [1]
Given Kudos: 11
Posts: 15
Kudos: 3
 [1]
Each year for 4 years, a farmer increased the number of trees in a 04 Nov 2018, 02:07
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi,

I tried using geometric progression formula for this ->
x is the no of trees at the end of 1st year, end of 2nd year no of trees is 5x/4. Therefore, common ratio (r) is 5/4

6250=x(r^n-1)
6250= x(5/4)^4-1
6250=x(5/4)^3
x=(6250*64)/125
x=3200

can you please explain to me where has my reasoning gone wrong?
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,860
 [1]
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,860
 [1]
Each year for 4 years, a farmer increased the number of trees in a 04 Nov 2018, 03:28
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
yashna36
Hi,

I tried using geometric progression formula for this ->
x is the no of trees at the end of 1st year, end of 2nd year no of trees is 5x/4. Therefore, common ratio (r) is 5/4

6250=x(r^n-1)
6250= x(5/4)^4-1
6250=x(5/4)^3
x=(6250*64)/125
x=3200

can you please explain to me where has my reasoning gone wrong?
Show more

Hey yashna36,
There is nothing wrong in your reasoning - you need to do one more step to get the final answer.

You have assumed x as the number of trees at the end of 1st year, whereas the question is asking us to find the number of trees at the beginning of the 1st year.

Therefore, you need to divide 3200 by 5/4 to get the final answer.

Hope this helps. :)
avatar
TheUltimateWinner
avatar
Schools: Harvard '24 Judge '23 LBS '24 McCombs '24 Mendoza Tepper '24 Ross '24 Cox Marshall '24 Fisher Kelley '24 Jones McDonough '24 Owen '24 Terry BU Simon '24 Katz GWU Mason Babson Gabelli Foster '24 Goizueta '24 Scheller Stern '23 CBS '23 Booth '23 Haas '25 Wharton '25 Stanford '26 Johnson'23 Fuqua '23 Kellogg '23 Kenan-Flagler'23 INSEAD Aug 22 intake Olin '23 Said '23 Sloan '23 Carey Arizona "22 Yale '23 UC Davis Madison '23 Anderson '23 Carroll Carlson '23 Darden '23
Posts: 2,465
Kudos: 2,456
 [1]
Each year for 4 years, a farmer increased the number of trees in a 02 Jul 2019, 04:20
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752

Can someone walk me through the logic behind this question. I am able to solve this by using options as well as by assuming the number of trees = x. However, had the question been, "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period". then it would have been difficult to solve.

Thanks

Say the number of trees at the beginning of the 4 year period was x, then:
At the end of the 1st year the number of trees would be \(x+\frac{1}{4}x=\frac{5}{4}*x\);
At the end of the 2nd year the number of trees would be \((\frac{5}{4})^2*x\);
At the end of the 3rd year the number of trees would be \((\frac{5}{4})^3*x\);
At the end of the 4th year the number of trees would be \((\frac{5}{4})^4*x\);
At the end of the \(n_{th}\) year the number of trees would be \((\frac{5}{4})^n*x\);

So, we have that \((\frac{5}{4})^4*x=6,250\) --> \(\frac{5^4}{4^4}*x=5^4*10\) --> \(x=4^4*10=2,560\).

Answer: D.

If the question were "if all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period", then we would have that: \((\frac{5}{4})^{15}*x=6,250\) --> \(x\neq{integer}\), so it would be a flawed question.

Hope it's clear.
Show more
Bunuel
In that time, the maker of the question will replace the figure 6250 with another one so that x has to be integer, right? :)
Thanks__
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,728
Own Kudos:
810,481
 [1]
Given Kudos: 105,800
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,728
Kudos: 810,481
 [1]
Each year for 4 years, a farmer increased the number of trees in a 02 Jul 2019, 04:24
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Asad
Bunuel
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752

Can someone walk me through the logic behind this question. I am able to solve this by using options as well as by assuming the number of trees = x. However, had the question been, "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period". then it would have been difficult to solve.

Thanks

Say the number of trees at the beginning of the 4 year period was x, then:
At the end of the 1st year the number of trees would be \(x+\frac{1}{4}x=\frac{5}{4}*x\);
At the end of the 2nd year the number of trees would be \((\frac{5}{4})^2*x\);
At the end of the 3rd year the number of trees would be \((\frac{5}{4})^3*x\);
At the end of the 4th year the number of trees would be \((\frac{5}{4})^4*x\);
At the end of the \(n_{th}\) year the number of trees would be \((\frac{5}{4})^n*x\);

So, we have that \((\frac{5}{4})^4*x=6,250\) --> \(\frac{5^4}{4^4}*x=5^4*10\) --> \(x=4^4*10=2,560\).

Answer: D.

If the question were "if all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period", then we would have that: \((\frac{5}{4})^{15}*x=6,250\) --> \(x\neq{integer}\), so it would be a flawed question.

Hope it's clear.
Bunuel
In that time, the maker of the question will replace the figure 6250 with another one so that x has to be integer, right? :)
Thanks__
Show more

Since x represent the number of trees, then it must be an integers, so if you were to replace 6,250 with some other number, you should replace it so that x at the end turns out to be an integer.
avatar
Netijyata
avatar
Joined: 13 Nov 2019
Last visit: 03 Dec 2019
Posts: 1
Posts: 1
Kudos: 0
Each year for 4 years, a farmer increased the number of trees in a 25 Nov 2019, 22:41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi, I am a still confused as to why we should consider the end of the first year. The question says that the number of trees is increasing every year. So if I take the first year say as one tree the second year will be 5/4. Can someone please explain why the first year itself is being considered as 5/4. What if the trees were planted at the year-end then they can be 5/4 in the end itself.
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
Each year for 4 years, a farmer increased the number of trees in a 26 Nov 2019, 22:40
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Netijyata
Hi, I am a still confused as to why we should consider the end of the first year. The question says that the number of trees is increasing every year. So if I take the first year say as one tree the second year will be 5/4. Can someone please explain why the first year itself is being considered as 5/4. What if the trees were planted at the year-end then they can be 5/4 in the end itself.
Show more

This is what the question says: "Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 ..."

The farmer increase the number of trees by 1/4 each year for 4 years. So he increases them by 1/4 in the first year, increases them by 1/4 in the second year, by 1/4 in the third year and by 1/4 in the fourth year. So say he increases them by 1/4 in 2016, 2017, 2018 and 2019.
To increase the number of trees by 1/4 in 2016, if there are 4 trees by the end of 2015, there will 5 trees by the end of 2016 because he increased them by 1/4 in 2016.
User avatar
adkor95
User avatar
Joined: 06 Mar 2020
Last visit: 10 Dec 2020
Posts: 30
Own Kudos:
14
Given Kudos: 80
Posts: 30
Kudos: 14
Each year for 4 years, a farmer increased the number of trees in a 26 Nov 2020, 03:46
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752

Can someone walk me through the logic behind this question. I am able to solve this by using options as well as by assuming the number of trees = x. However, had the question been, "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period". then it would have been difficult to solve.

Thanks

The number of trees increases by 1/4 i.e. 25% every year. It is just a matter of thinking in terms of successive percentage changes e.g. population increase. Here, we are talking about the increase of tree population.

If x increases by 25%, how we denote it? (5/4)*x
If next year, this new number increases by 25% again, how do we denote it? (5/4)*(5/4)*x
and so on...

For more on this, check: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/02 ... e-changes/

So if we are taking into account 4 years, we simply get (5/4)^4 * x = 6250

As for your next question, the numbers given would be such that the calculation will not be tough.

Say, you have 8 years and 100% increase every year (population doubles every year). The final population will be divisible by 2^8 i.e. 256.
Something like 2^8 * x = 2560

and if you meant what you wrote (though I considered that the 4 was a typo because of the language of the question) "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period", note that you still need to work with

(5/4)^4 * x = 6250
since you need the number of trees 4 yrs back only. The only thing is that the answer (2560) needs to be divisible by \(5^{11}\) which it isn't so there is a problem in this question. If it were an actual question, the answer would be divisible by \(5^{11}\) but you wouldn't really need to bother about it.
Show more

Thanks! But how do you know when to solve difficult fractions, rather than to use a shortcut? I guessed on the question because I figured I had missed a strategy to avoid solving (1.25)^4 or (5/4)^4
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [2]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [2]
Each year for 4 years, a farmer increased the number of trees in a 26 Nov 2020, 04:18
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
adkor95
VeritasKarishma
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752

Can someone walk me through the logic behind this question. I am able to solve this by using options as well as by assuming the number of trees = x. However, had the question been, "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period". then it would have been difficult to solve.

Thanks

The number of trees increases by 1/4 i.e. 25% every year. It is just a matter of thinking in terms of successive percentage changes e.g. population increase. Here, we are talking about the increase of tree population.

If x increases by 25%, how we denote it? (5/4)*x
If next year, this new number increases by 25% again, how do we denote it? (5/4)*(5/4)*x
and so on...

For more on this, check: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/02 ... e-changes/

So if we are taking into account 4 years, we simply get (5/4)^4 * x = 6250

As for your next question, the numbers given would be such that the calculation will not be tough.

Say, you have 8 years and 100% increase every year (population doubles every year). The final population will be divisible by 2^8 i.e. 256.
Something like 2^8 * x = 2560

and if you meant what you wrote (though I considered that the 4 was a typo because of the language of the question) "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period", note that you still need to work with

(5/4)^4 * x = 6250
since you need the number of trees 4 yrs back only. The only thing is that the answer (2560) needs to be divisible by \(5^{11}\) which it isn't so there is a problem in this question. If it were an actual question, the answer would be divisible by \(5^{11}\) but you wouldn't really need to bother about it.

Thanks! But how do you know when to solve difficult fractions, rather than to use a shortcut? I guessed on the question because I figured I had missed a strategy to avoid solving (1.25)^4 or (5/4)^4
Show more

adkor95

You don't have to solve (5/4)^4 here.

Note that you have
(5/4)^4 * x = 6250

sNow recognise that 5^4 = 625 (you should know the first few exponents)

x/4^4 = 10

x = 4^4 * 10 = 2^8 * 10 = 256 * 10

Again note that 2^8 = 256 is something you should know.

You should know powers till 2^10, 3^6, 5^4, squares all numbers till 20 and cubes of all numbers till 10.
User avatar
PersonGuy
User avatar
Joined: 17 Feb 2020
Last visit: 23 Jul 2022
Posts: 17
Own Kudos:
5
Given Kudos: 10
Posts: 17
Kudos: 5
Each year for 4 years, a farmer increased the number of trees in a 04 Feb 2021, 18:50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can someone please explain to me why this answer is wrong:

1st year = x
2nd year = 5x/4
3rd year = 25x/16
4th year = 125x/64

125x/64 = 6250

Why am I not starting and finishing year 1 with X and then beginning the increase at year 2? What language am I missing that is making me think the process to solve is the one immediately above?

VeritasKarishma
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [2]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [2]
Each year for 4 years, a farmer increased the number of trees in a 04 Feb 2021, 23:25
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PersonGuy
Can someone please explain to me why this answer is wrong:

1st year = x
2nd year = 5x/4
3rd year = 25x/16
4th year = 125x/64

125x/64 = 6250

Why am I not starting and finishing year 1 with X and then beginning the increase at year 2? What language am I missing that is making me think the process to solve is the one immediately above?

VeritasKarishma
Show more


"Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year."

For 4 years, every year the farmer increased number of trees by 1/4th.
So in year 1, he increased the number of trees by 1/4th. In year 2, he did the same again and so on in years 3 and 4 too.
You have missed the increase in year 1. Before year 1 if number of trees was x, in year 1, it increased by 1/4 to become 5x/4.
User avatar
avigutman
User avatar
Joined: 17 Jul 2019
Last visit: 30 Sep 2025
Posts: 1,285
Own Kudos:
1,906
 [1]
Given Kudos: 66
Location: Canada
Schools: NYU Stern (WA)
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Expert
Expert reply
Schools: NYU Stern (WA)
GMAT 3: 770 Q50 V45
Posts: 1,285
Kudos: 1,906
 [1]
Each year for 4 years, a farmer increased the number of trees in a 27 Aug 2021, 16:42
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 21 Apr 2026
Posts: 6,976
Own Kudos:
16,892
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,976
Kudos: 16,892
 [1]
Each year for 4 years, a farmer increased the number of trees in a 18 Oct 2021, 07:57
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752
Show more


Answer: Option D

Step-by-Step Video solution by GMATinsight


User avatar
woohoo921
User avatar
Joined: 04 Jun 2020
Last visit: 17 Mar 2023
Posts: 493
Own Kudos:
149
 [1]
Given Kudos: 623
Posts: 493
Kudos: 149
 [1]
Each year for 4 years, a farmer increased the number of trees in a 04 Mar 2022, 18:46
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
KarishmaB
I have two questions:
-When you say "So if initially the number of trees was x, in the first year he made them (5/4)x" to clarify... at time zero the number of trees was x, correct?
-At first, I was solving for the number of trees for year 1. I see how it can be easy to mistake year 1 for time zero when the question asks for "at the beginning of the 4-year period"... are there other Official Guide problems that you recommend looking at in this nature for more practice?

Thank you!
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [2]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [2]
Each year for 4 years, a farmer increased the number of trees in a 04 Mar 2022, 20:06
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
woohoo921
KarishmaB
I have two questions:
-When you say "So if initially the number of trees was x, in the first year he made them (5/4)x" to clarify... at time zero the number of trees was x, correct?
-At first, I was solving for the number of trees for year 1. I see how it can be easy to mistake year 1 for time zero when the question asks for "at the beginning of the 4-year period"... are there other Official Guide problems that you recommend looking at in this nature for more practice?

Thank you!
Show more

Yes, you start with number x. Think of it as the principal you have in compound interest problems.
We begin with a certain value and then apply successive percentage changes to it over time periods.
avatar
Engineer1
avatar
Joined: 01 Jan 2014
Last visit: 23 Jan 2026
Posts: 195
Own Kudos:
764
Given Kudos: 457
Location: United States
Concentration: Strategy, Finance
Schools: Booth (Chicago) (M$)
Schools: Booth (Chicago) (M$)
Posts: 195
Kudos: 764
Each year for 4 years, a farmer increased the number of trees in a 14 Sep 2023, 12:18
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
imhimanshu
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 6250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.

A. 1250
B. 1563
C. 2250
D. 2560
E. 2752

Can someone walk me through the logic behind this question. I am able to solve this by using options as well as by assuming the number of trees = x. However, had the question been, "If all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period". then it would have been difficult to solve.

Thanks

Say the number of trees at the beginning of the 4 year period was x, then:
At the end of the 1st year the number of trees would be \(x+\frac{1}{4}x=\frac{5}{4}*x\);
At the end of the 2nd year the number of trees would be \((\frac{5}{4})^2*x\);
At the end of the 3rd year the number of trees would be \((\frac{5}{4})^3*x\);
At the end of the 4th year the number of trees would be \((\frac{5}{4})^4*x\);
At the end of the \(n_{th}\) year the number of trees would be \((\frac{5}{4})^n*x\);

So, we have that \((\frac{5}{4})^4*x=6,250\) --> \(\frac{5^4}{4^4}*x=5^4*10\) --> \(x=4^4*10=2,560\).

Answer: D.

If the question were "if all of the trees thrived and there were 6250 trees in the orchard at the end of 15 year period, how many trees were in the orchard at the beginning of the 4 year period", then we would have that: \((\frac{5}{4})^{15}*x=6,250\) --> \(x\neq{integer}\), so it would be a flawed question.

Hope it's clear.
Show more


Should not this be : (5/4)^3 * x trees at the beginning of year 4? x is the number of trees at the beginning of year 1. I am confused how the correct answer is value of x.
   1   2   3   
Moderators:
Bunuel
Math Expert
109728 posts
Krunaal
Tuck School Moderator
853 posts