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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
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I solved by converting the question in pictorial form. It made the question much more easier to solve!

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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
let large be 12 ltrs so its filled to 4 ltrs
and small is 8 ltrs and filled to 6 ltrs
6+4 ; 10 ltrs
10/12 ; 5/6
IMO A:



Two bottles are partially filled with water. The larger bottle currently holds 1/3 of its capacity. The smaller bottle, which has 2/3 of the capacity of the larger bottle, currently holds 3/4 of its capacity. If the contents of the smaller bottle are poured into the larger bottle, the larger bottle will be filled to what fraction of its capacity?

A. 5/6

B. 3/4

C. 2/3

D. 7/12
E. 1/2
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
IMO correct answer is A

attachment provided as explanation
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
Capacity of Large bottle = L. Amount of water in large bottle \(= \frac{1}{3}\) L

Capacity of Small bottle = S. Amount of water in small bottle \(= \frac{3}{4} S\). Since \(S = \frac{2}{3}\) L
 Amount of water in small bottle = \(\frac{3}{4} * \frac{2}{3}\) L \(= \frac{1}{2}\) L

Now adding water from small to Large bottle gives = \(\frac{1}{3} + \frac{1}{2}\) L
 \(= \frac{5}{6}\) L

Answer (A).
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
Let the larger bottle has 120L capacity.
And larger bottle is filled to 1/3 capacity, hence it will have 40L.
Smaller will be 2/3 of 120 = 80L, and it currently holds 3/4 of 80 = 60
so 60+40=100 i.e. 100/120 = 5/6 (A)


Two bottles are partially filled with water. The larger bottle currently holds 1/3 of its capacity. The smaller bottle, which has 2/3 of the capacity of the larger bottle, currently holds 3/4 of its capacity. If the contents of the smaller bottle are poured into the larger bottle, the larger bottle will be filled to what fraction of its capacity?

A. 5/6
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
Consider the capacity is first vessel to be 12 l. And 1/3 of 12= 4 l
As per the statement the capacity of the second container becomes 8 l. And 3/4 of 8= 6 l

Hence, (4+6)/12=5/6

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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
Consider the capacity is first vessel to be 12 l. And 1/3 of 12= 4 l
As per the statement the capacity of the second container becomes 8 l. And 3/4 of 8= 6 l

Hence, (4+6)/12=5/6

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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
If we tAke the capacity of larger bottle to be 12,then it's filled with (1/3)*12=4 . Smaller bottle is filled to(3/4)* (2/3)*12=6

6 is poured into larger bottle,total becomes 10 so, the capacity now is (10/12)=5/6
Option A is the answer
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
Let the capacity of large bottle be x
filled = 1/3x
small bottler capacity in terms of large = 2/3x
filled = 3/4*2/3x
= 1/2x
total water = 1/3x+1/2x
= 5/6x
Ans = A
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Re: Two bottles are partially filled with water. The larger bottle current [#permalink]
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