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Re: Users' Self Made Questions  [#permalink]

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New post 08 Oct 2019, 14:33
A person travelled 300 km by train and another 200 km by bus. The journey took a total time of 5 hours and 30 minutes. However, if the person had travelled 260 km by train and 240 km by bus, the journey would have taken a total time of six more minutes than the original time. What was the speed of the train in km per hour?

(A) 80

(B) 100

(C) 110

(D) 120

(E) 130
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New post 09 Oct 2019, 13:56
Hovkial wrote:
A person travelled 300 km by train and another 200 km by bus. The journey took a total time of 5 hours and 30 minutes. However, if the person had travelled 260 km by train and 240 km by bus, the journey would have taken a total time of six more minutes than the original time. What was the speed of the train in km per hour?

(A) 80

(B) 100

(C) 110

(D) 120

(E) 130


Let speed of train = V, speed of bus = W

Then:

(300/V) + (200/W) = 11/2 ......................... (Equation 1)

(260/V) + (240/W) = 336/60 ....................... (Equation 2)

Solving:

V = 100 km/hr

ANSWER: (B)
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New post 13 Oct 2019, 04:28
1
All the positive integers less than 1000 but not containing the digit '5' are arranged horizontally in descending order. What is the 555th number on the list?

A. 209
B. 210
C. 211
D. 212
E. 213
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New post 13 Oct 2019, 05:11
nick1816 wrote:
All the positive integers less than 1000 but not containing the digit '5' are arranged horizontally in descending order. What is the 555th number on the list?

A. 209
B. 210
C. 211
D. 212
E. 213


giving a try
for a range of no from 0-99 ; we have 1+(8*10) ; 81 values without '5'
since the arrangement of no is done in descending order so
from 600 to 999 we have ; 81* 4 ; 324 positions
400 to 499 ; 81 positions ; 324+81 ; 405
200 to 399 ; 81*2 ; 162 +405 ; 567 postions
so no 200 is 567th
555th no ; 567-555 ; 12th from 200 + 1 missing 205 ; i.e 213 shall be 555th term
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New post 26 Nov 2019, 20:15
Solution of the Question shall be as per attached sketch
Attachment:
Solution.jpeg
Solution.jpeg [ 78.51 KiB | Viewed 129 times ]



gmatbusters wrote:
Hi math experts, try this question and provide feedback...

Janvisahu wrote:
Image
Triangle ABC is a right angled triangle with right angle at Vertex B. Triangle DEF is an equilateral triangle with side 10 cm. The lengths of sides (in cm) are marked in the Drawing. What is the area of the polygon ABFEGA?

(1) The length of CD (overlap of sides) is 3 cm.
(2) The length of altitude (GH) of triangle GDC is 2.598 cm.


Spoiler: :: OA
D


Spoiler: ::
Attachment:
The attachment Triangle.jpg is no longer available

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Re: Users' Self Made Questions   [#permalink] 26 Nov 2019, 20:15
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