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Updated on: 06 Jul 2019, 05:22
Originally posted by stonecold on 18 Apr 2017, 04:54.
Last edited by Sajjad1994 on 06 Jul 2019, 05:22, edited 1 time in total.
Last edited by Sajjad1994 on 06 Jul 2019, 05:22, edited 1 time in total.
Added Source
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
44% (02:10) correct
56%
(01:36)
wrong
based on 191
sessions
History
Date
Time
Result
Not Attempted Yet
How many different ways can 3 cubes be painted if each cube is painted with one colour and only three colours red,green and blue are available?(Order is not considered, for example green,green,blue is considered the same as green blue green)
A)27
B)10
C)9
D)3
E)2
A)27
B)10
C)9
D)3
E)2
Source: Nova GMAT
Difficulty Level: 750
Difficulty Level: 750
18 Apr 2017, 05:04
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stonecold
XXX - 3 cases (red, red, red; green, green, green; blue, blue, blue)
XXY - \(C^1_3*2 = 6\), where \(C^1_3\) is the number of ways to choose which color will be used for two identical colored cubes (XX) and *2 because there will be 2 colors left to choose from for Y.
XYZ - 1 case (red, green, blue)
3 + 6 + 1 = 10.
Answer: B.
General Discussion
18 Apr 2017, 05:14
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stonecold
Hi..
Yes picking up indl cases would be better easier and less error prone.
1) all of same colour-3
2) two of same colour..
Two colours can be choosen in 3C2=3!/2!=3 ways and any of these two can be on TWO cubes. So 3*2=6
3) all of one colour-1..
Total -- 3+6+1=10
B
