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Sub 505 (Easy)|   Sequences|      
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 23 Mar 2020, 08:50
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

84% (01:19) correct 16% (01:42) wrong based on 270 sessions

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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term. What is the remainder when the 75th term
is divided by 9?

A) 3
B) 5
C) 6
D) 7
E) 8
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Official Answer
B
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 26 Mar 2020, 09:34
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Asad
In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term. What is the remainder when the 75th term
is divided by 9?

A) 3
B) 5
C) 6
D) 7
E) 8
Show more

a75= 4+75*5 ; 374
remainder would be when divided by 9 ; 5
IMO B
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 26 Mar 2020, 10:58
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Solution



Given
In this question, we are given that
    • In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term

To find
We need to determine
    • The remainder when the 75th term is divided by 9

Approach and Working out
The given sequence is an AP with the first term a = 4 and common difference d = 5
    • The value of the 75th term of the sequence = \(t_{75}\) = a + (75 – 1) d = 4 + 74 x 5 = 374
    • Hence, the remainder = R(\(\frac{374}{9}\)) = R(\(\frac{3 + 7 + 4}{9}\)) = 5

Thus, option B is the correct answer.

Correct Answer: Option B
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 17 Apr 2022, 16:23
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Archit3110
Asad
In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term. What is the remainder when the 75th term
is divided by 9?

A) 3
B) 5
C) 6
D) 7
E) 8

a75= 4+75*5 ; 374
remainder would be when divided by 9 ; 5
IMO B
Show more


Hi,

It should be [4+74*5] = [374]

Kindly correct me if I am missing something.

Regards.
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 17 Apr 2022, 22:11
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Is there anything wrong with just noticing that the pattern alternates between remainder 5 (for odd values of n) and 0 (for even values of n)? So the 75th value is an odd nth value, so the remainder will be 5.

Is this something that might get me in trouble on harder questions?
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In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previo 12 Jun 2024, 16:58
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