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23 Mar 2020, 08:50
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
84% (01:19) correct
16%
(01:42)
wrong
based on 264
sessions
History
Date
Time
Result
Not Attempted Yet
In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term. What is the remainder when the 75th term
is divided by 9?
A) 3
B) 5
C) 6
D) 7
E) 8
is divided by 9?
A) 3
B) 5
C) 6
D) 7
E) 8
Archit3110
26 Mar 2020, 09:34
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Asad
a75= 4+75*5 ; 374
remainder would be when divided by 9 ; 5
IMO B
26 Mar 2020, 10:58
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Solution
Given
In this question, we are given that
- • In the sequence 4, 9, 14, 19,…, each term is 5 greater than the previous term
To find
We need to determine
- • The remainder when the 75th term is divided by 9
Approach and Working out
The given sequence is an AP with the first term a = 4 and common difference d = 5
- • The value of the 75th term of the sequence = \(t_{75}\) = a + (75 – 1) d = 4 + 74 x 5 = 374
• Hence, the remainder = R(\(\frac{374}{9}\)) = R(\(\frac{3 + 7 + 4}{9}\)) = 5
Thus, option B is the correct answer.
Correct Answer: Option B
