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brains
VeritasKarishma and Bunuel .

Help please!

I could not find any combinations other than y being 3 from first statement. So i think statement 1 is sufficient. Kindly explain . However OA is given as C in the post
Thanks

Hi brains

For statement 1 we can have the following cases

\(x=2, y=3\)

\(x=\sqrt[3]{648}, y=1\)

Note that we are not told in statement 1 that \(x\) must be an integer

Hope this helps

Posted from my mobile device
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If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient
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If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient

All integers including negative ones must be either even or odd.

Even - {......, -6, -4, -2, 0, 2, 4, 6, ....}

Odd - {....., -5, -3, -1, 1, 3, ....}

Posted from my mobile device
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firas92
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If y is an odd number and \(x^3*y^4=648\), y=?



1) y is positive.

2) x is an integer.


The issue is,why would we need the first statement.Negative numbers are not even or odd. 2 must be sufficient

All integers including negative ones must be either even or odd.

Even - {......, -6, -4, -2, 0, 2, 4, 6, ....}

Odd - {....., -5, -3, -1, 1, 3, ....}

Posted from my mobile device


Ok, thanks for clearing up the misunderstanding I had. C makes sense then
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brains
VeritasKarishma and Bunuel .

Help please!

I could not find any combinations other than y being 3 from first statement. So i think statement 1 is sufficient. Kindly explain . However OA is given as C in the post
Thanks

Hi brains

For statement 1 we can have the following cases

\(x=2, y=3\)

\(x=\sqrt[3]{648}, y=1\)

Note that we are not told in statement 1 that \(x\) must be an integer

Hope this helps

Posted from my mobile device

Without statement 2, y can be 1 and x = cube root of 648
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