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22 Apr 2019, 12:13
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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Question Stats:
65% (01:26) correct
35%
(01:22)
wrong
based on 86
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Given n is a prime number, how many trailing zeroes are in the digit of n! ?
1) n! is divisible by 25
2) n! is not divisible by 125
1) n! is divisible by 25
2) n! is not divisible by 125
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22 Apr 2019, 18:45
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I think it's 'C' and the number of trailing zeroes in n! should be 2.
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23 Apr 2019, 02:49
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We can find the number of trailing zeros of n! by knowing the number of 5's in n!
Using only statement 1
1) if n! is divisible by 25, it has at least two 5's. This tells us that the number of 0's >= 2. Possible values are 2,3,4,5,6.........
INSUFFICIENT
Using only statement 2
2) if n! is not divisible by 125, then it has fewer than three 5's. This tells us that the number of 0's < 3. Possible values are only 0,1,2
INSUFFICIENT
Combining statements 1 and 2: The only common value is 2.
SUFFICIENT
Using only statement 1
1) if n! is divisible by 25, it has at least two 5's. This tells us that the number of 0's >= 2. Possible values are 2,3,4,5,6.........
INSUFFICIENT
Using only statement 2
2) if n! is not divisible by 125, then it has fewer than three 5's. This tells us that the number of 0's < 3. Possible values are only 0,1,2
INSUFFICIENT
Combining statements 1 and 2: The only common value is 2.
SUFFICIENT
