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19 Mar 2021, 09:03
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
69% (01:09) correct
31%
(01:20)
wrong
based on 55
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Is the sum of three consecutive even integers zero?
1) The product of the three consecutive even integers is zero
2) The sum of the least and the greatest integer is zero
1) The product of the three consecutive even integers is zero
2) The sum of the least and the greatest integer is zero
19 Mar 2021, 09:29
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Is the sum of three consecutive integers = 0?
Let three consecutive integers = n, n + 2 and n + 4.
Is n + n + 2 + n + 4 = 3n + 6 = 0?
Statement 1:
n * (n + 2) * (n + 4) = 0
In this case, any one of the three numbers can be 0.
Case 1: n = 0, then, n + 2 = 2, and n + 4 = 4.
Sum = 3n + 6 = 3 * 0 + 6 = 6 \(\neq\) 0
Case 2: n + 2 = 0 => n = -2, and n + 4 = 2
Sum = 3n + 6 = 3 * (-2) + 6 = 0
Case 3: n + 4 = 0 (not needed as we got two different answers for above two cases, still can check this case)
Statement 1 is Not Sufficient.
Statement 2:
n + (n + 4) = 0
=> 2n + 4 = 0
=> n = -2
Sum = 3n + 6 = 3 * (-2) + 6 = 0
Statement 2 is Sufficient.
So, correct answer is option B.
Let three consecutive integers = n, n + 2 and n + 4.
Is n + n + 2 + n + 4 = 3n + 6 = 0?
Statement 1:
n * (n + 2) * (n + 4) = 0
In this case, any one of the three numbers can be 0.
Case 1: n = 0, then, n + 2 = 2, and n + 4 = 4.
Sum = 3n + 6 = 3 * 0 + 6 = 6 \(\neq\) 0
Case 2: n + 2 = 0 => n = -2, and n + 4 = 2
Sum = 3n + 6 = 3 * (-2) + 6 = 0
Case 3: n + 4 = 0 (not needed as we got two different answers for above two cases, still can check this case)
Statement 1 is Not Sufficient.
Statement 2:
n + (n + 4) = 0
=> 2n + 4 = 0
=> n = -2
Sum = 3n + 6 = 3 * (-2) + 6 = 0
Statement 2 is Sufficient.
So, correct answer is option B.
25 Mar 2021, 15:19
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Am I missing something?
St1 -
x = 0, y = 1, z = 2 ---> 1 + 2 + 0 = 3
x = -1, y = 1, z = 0 ---> -1 + 1 + 0 = 0
Insufficient
St2 -
x = -1, y = 0, z = 1 ---> -1 + 1 + 0 = 0 YES
x = -2, y = 1, z = 2 ---> -2 + 1 + 2 = 1 NO
Shouldn't St2 be insufficient?
St1 -
x = 0, y = 1, z = 2 ---> 1 + 2 + 0 = 3
x = -1, y = 1, z = 0 ---> -1 + 1 + 0 = 0
Insufficient
St2 -
x = -1, y = 0, z = 1 ---> -1 + 1 + 0 = 0 YES
x = -2, y = 1, z = 2 ---> -2 + 1 + 2 = 1 NO
Shouldn't St2 be insufficient?
