sa800
does a odd root ALWAYS have one solution whereas an even root has multiple solutions?
If you're asking about equations like
x^3 = 216
or
t^5 = -32
where we're raising an unknown to an odd power, and that's equal to some number, then yes, there is always exactly one solution when the exponent is odd. If instead we have the same situation, but with an even power, there are three possibilities. If the result is equal to a positive number, e.g.
x^2 = 16
or
t^4 = 625
then there will be two solutions, one positive and one negative (4 and -4 to the first equation, 5 and -5 to the second), unless some restriction in the question obligates the solution to be positive (e.g. if x is a length or a number of cans in a warehouse, it cannot be negative).
If the result is equal to zero, there is just one solution, namely zero, so:
x^2 = 0
has only one solution, x = 0.
And if the result is equal to a negative number, which you shouldn't see on the GMAT, then there are no real solutions, so the equations:
x^4 = -64
or
t^2 = -9
have no real number solutions.