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What is the circumference of the circle above with center O?

(1) The perimeter of triangle OXZ is \(20 + 10\sqrt{2}\). Since <O=90 degrees and OX=OZ=r, then \(XZ=r\sqrt{2}\). Thus we have that \(r+r+r\sqrt{2}=20 + 10\sqrt{2}\) --> we can find r, thus we can find the circumference. Sufficient.

(2) The length of arc XYZ is \(5\pi\). Again, since <O=90 degrees, then the length of arc XYZ is 1/4 of the circumference (360 degrees), thus the circumference = \(20\pi\). Sufficient.

Re: What is the circumference of the circle above with center O? [#permalink]

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12 Jan 2013, 08:33

Bunuel wrote:

What is the circumference of the circle above with center O?

(1) The perimeter of triangle OXZ is \(20 + 10\sqrt{2}\). Since <O=90 degrees and OX=OZ=r, then \(XZ=r\sqrt{2}\). Thus we have that \(r+r+r\sqrt{2}=20 + 10\sqrt{2}\) --> we can find r, thus we can find the circumference. Sufficient.

(2) The length of arc XYZ is \(5\pi\). Again, since <O=90 degrees, then the length of arc XYZ is 1/4 of the circumference (360 degrees), thus the circumference = \(20\pi\). Sufficient.

Answer: D.

Is there a formula for this explanation?
_________________

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Amazing Free video explanation for all Quant questions from OG 13 and much more http://www.gmatquantum.com/og13th/

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What is the circumference of the circle above with center O?

(1) The perimeter of triangle OXZ is \(20 + 10\sqrt{2}\). Since <O=90 degrees and OX=OZ=r, then \(XZ=r\sqrt{2}\). Thus we have that \(r+r+r\sqrt{2}=20 + 10\sqrt{2}\) --> we can find r, thus we can find the circumference. Sufficient.

(2) The length of arc XYZ is \(5\pi\). Again, since <O=90 degrees, then the length of arc XYZ is 1/4 of the circumference (360 degrees), thus the circumference = \(20\pi\). Sufficient.

Answer: D.

Is there a formula for this explanation?

Yes, check here: math-circles-87957.html (see Arc Length under Arcs and Sectors chapter)
_________________

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02 Jan 2015, 07:56

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Even though this DS question is about Geometry rules, it involves a great Algebra shortcut that you'll see at least once on Test Day.

We're given a circle with an ISOSCELES right triangle within it (with the 3 vertices at the center of the circle and on the circumference), so we have a 45/45/90 right triangle. We're asked for the circumference of the circle.

Fact 1: The perimeter of triangle OXZ = 20 + 10\sqrt{2}

Since the triangle is a 45/45/90, we know the sides are A, A and A\sqrt{2}, thus...

A + A + A\sqrt{2} = 20 + 10\sqrt{2}

We have ONE VARIABLE and ONE equation, so we CAN solve it (and since there are no additional possible answers, re. due to exponents, absolute values, etc. - there will be JUST ONE ANSWER.) Fact 1 is SUFFICIENT.

Fact 2: Arc XYZ = 5pi

Since this arc is based on a 90 degree angle, we CAN figure out what fraction of the circumference we're dealing with (it's 1/4, but that math is not necessary). In this way we have the SAME shortcut that we had in Fact 1: ONE VARIABLE and ONE equation, so we CAN solve it. Fact 2 is SUFFICIENT.

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02 Jan 2017, 15:32

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: What is the circumference of the circle above with center O? [#permalink]

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06 Jul 2017, 17:48

We need to find the value of \(2 \pi R\) From the figure we can tell that OX=OZ = radius or R. Since these two sides are equal and the other angle is given as \(90^ {\circ}\), triangle XOZ is an isosceles right triangle with sides \(x:x:x\sqrt{2}\)

Armed with this info, lets look at the statements:

Statement 1: Perimeter = \(20+10\sqrt{2}\) This straight away gives us the radius as 10..........................Sufficient

Statement 2: Length of arc XYZ = \(5\pi\) We know that Length of an arc = \(x^{\circ}\) * Circumference/360 Therefore, \(5\pi\) = 90 * 2 * \(\pi\) * R/360 We can find the circumference..........................Sufficient

Answer is D _________________

Kudosity killed the cat but your kudos can save it.

What is the circumference of the circle above with center O?

(1) The perimeter of triangle OXZ is \(20 + 10\sqrt{2}\). (2) The length of arc XYZ is \(5\pi\).

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

By Variable Approach method, we can identify a circle with just 1 varable, which is a radius. Thus D is the answer most likely. Let \(r\) be the radius of the above circle.

Condition 1) \(2 \cdot r + r\sqrt{2} = r \cdot (2 + \sqrt{2} ) = 20 + 10\sqrt{2}\) Thus \(r = 10\). This condition is sufficient.

Condition 2) The arc XYZ is \(\frac{1}{4} \cdot 2 \pi r = 5 \pi\). Thus \(r = 10\). This condition is also sufficient.

Therefore D is the answer as expected.

-> For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
_________________

Re: What is the circumference of the circle above with center O? [#permalink]

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07 Jul 2017, 22:48

Answer is D 1. Traingle is 45,45,90 degree triangle. So two sides are same and length of radius is 10 Circumference of circle is 20pi 2. Is an arc is is known and angle subtending that arc is known than radius can be calculated. So Both 1 and 2 are sufficient.

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