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15 Mar 2018, 08:28
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:24) correct
24%
(01:38)
wrong
based on 68
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Time
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Not Attempted Yet
What is the value of x?
Capture1.JPG [ 21.87 KiB | Viewed 2527 times ]
(A) 1
(B) 4/3
(C) 3/2
(D) 5/4
(E) 5/2
Attachment:
Capture1.JPG [ 21.87 KiB | Viewed 2527 times ]
(A) 1
(B) 4/3
(C) 3/2
(D) 5/4
(E) 5/2
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15 Mar 2018, 08:43
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itisSheldon
It is 30-60-90 triangle...
corresponding sides ratio is \(1:\sqrt{3}:2\)...
\(\frac{opposite 30}{opposite 90} = \frac{1}{2} = \frac{x+1}{4x-3}\)..
\(4x-3=2x+2........2x=5.....x=\frac{5}{2}\)
E
16 Aug 2019, 07:40
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For geometry questions where triangles are involved is really important to know sen, cos and tg of 0º 30º,45º, 60º and 90º
Hereunder a rule to remember all of them by just learning the values for sen
sen0º=0 (easy to remember because both are 0)
sen30º=1/2
sen45º=((2)^1/2)/2
sen60º=((3)^1/2)/2
sen 90=1 (easy to remember)
so you just need to memorize by heart sen30º and sen60º. The others are easy to remember
Now let's find out cos. You don't need to memorize. Just make the opposite from sen to get cos
sen0º=cos90º
sen30º=cos60º
sen45º=cos45º
sen60º=cos30º
sen90º=cos0º
Easy to remember right?
Finally to do tg, you just need to divide sen/cos. Don't memorize any of the tg forumlas. Tg are barely needed and if you finally need it for a questions just do sen/cos
Let's solve the question now:
we choose cos because we have info about the adjacent leg
cos60º=1/2=(x+1)/4x-3;
4x-3=2x+2 --->2x=5---> x=5/2
OPTION E
Hereunder a rule to remember all of them by just learning the values for sen
sen0º=0 (easy to remember because both are 0)
sen30º=1/2
sen45º=((2)^1/2)/2
sen60º=((3)^1/2)/2
sen 90=1 (easy to remember)
so you just need to memorize by heart sen30º and sen60º. The others are easy to remember
Now let's find out cos. You don't need to memorize. Just make the opposite from sen to get cos
sen0º=cos90º
sen30º=cos60º
sen45º=cos45º
sen60º=cos30º
sen90º=cos0º
Easy to remember right?
Finally to do tg, you just need to divide sen/cos. Don't memorize any of the tg forumlas. Tg are barely needed and if you finally need it for a questions just do sen/cos
Let's solve the question now:
we choose cos because we have info about the adjacent leg
cos60º=1/2=(x+1)/4x-3;
4x-3=2x+2 --->2x=5---> x=5/2
OPTION E
