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26 Aug 2017, 06:27
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D
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Difficulty:
75%
(hard)
Question Stats:
43% (01:57) correct
57%
(01:52)
wrong
based on 96
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x*y is a prime number greater than 2 where x and y are positive integers.
What is the unit digit of 4^x + 3^y
1) x > 39
2) y=1
Source: www.GMATinsight.com
What is the unit digit of 4^x + 3^y
1) x > 39
2) y=1
Source: www.GMATinsight.com
26 Aug 2017, 07:35
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GMATinsight
Hi...
Quote:
MEANS
One of x or y is surely 1 and other some ODD number..
\(4^x+3^y\)
lets see the statements
1) x>39
this means y =1 ...
so \(4^x+3^y=4^x+3^1=4^x+3\)
now x can take various values but ONLY ODD and each of this value will be of type 4a+1 or 4a+3..
\(4^{odd.. number}\) will always have 4 as units digit.. example \(4^1=4..4^3=64\)
so units digit will be 4+3=7
sufficient
2) y=1..
same as above
suff
D
gmatexam439
26 Aug 2017, 09:53
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x*y is a prime number greater than 2 where x and y are positive integers.
What is the unit digit of 4^x + 3^y
1) x > 39
2) y=1
x*y = prime > 2;
Few things to be kept in mind:
1. All primes greater than 2 are odd
2. A prime has only 2 factors: 1 and itself
Statement 1:
X>odd # greater than 39; so, y must be 1.
4^odd will have 4 as units digit; 3^1 = 3; Thus units digit will always be 7 --> SUFFICIENT
Statement 2:
y=1; then, x=odd number.
4^odd will have 4 as units digit; 3^1 = 3; Thus units digit will always be 7 --> SUFFICIENT
Answer: D
What is the unit digit of 4^x + 3^y
1) x > 39
2) y=1
x*y = prime > 2;
Few things to be kept in mind:
1. All primes greater than 2 are odd
2. A prime has only 2 factors: 1 and itself
Statement 1:
X>odd # greater than 39; so, y must be 1.
4^odd will have 4 as units digit; 3^1 = 3; Thus units digit will always be 7 --> SUFFICIENT
Statement 2:
y=1; then, x=odd number.
4^odd will have 4 as units digit; 3^1 = 3; Thus units digit will always be 7 --> SUFFICIENT
Answer: D
