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A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the perimeter of the triangle is 20, what is the length of the longest side?
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
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29 Aug 2017, 02:31
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Bunuel
A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the perimeter of the triangle is 20, what is the length of the longest side?
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
x-2+2x-3+x+1 = 20
x=6
sides will be 4, 9, 7
A
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29 Aug 2017, 02:47
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Bunuel
A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the perimeter of the triangle is 20, what is the length of the longest side?
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
Perimeter \(= (x -2) + (2x-3)+ (x+1) = 20\)(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
\(x - 2 + 2x - 3 + x + 1 = 20\)
\(4x - 4 = 20\)
\(4x = 20+4 = 24\)
\(x = \frac{24}{4} = 6\)
Lets put value of \(x\) in the above sides to check which side is longest side.
\(x – 2 = 6 - 2 = 4\)
\(2x – 3 = (2*6) - 3 = 12-3 = 9\)
\(x + 1 = 6 + 1 = 7\)
Therefore Sides are \(4,7\) and \(9\).
Longest side \(= 9\)
Answer (A)...
