A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the peri

Question

A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the perimeter of the triangle is 20, what is the length of the longest side?

(A) 9 
(B) 8 
(C) 7
(D) 6 
(E) 5

Luckisnoexcuse · Answer

x-2+2x-3+x+1 = 20
x=6
sides will be 4, 9, 7

A

sashiim20 · Answer

Perimeter  = (x -2) + (2x-3)+ (x+1) = 20

x - 2 + 2x - 3 + x + 1 = 20

4x - 4 = 20

4x = 20+4 = 24

x = \frac{24}{4} = 6

Lets put value of  x  in the above sides to check which side is longest side.

x – 2 = 6 - 2 = 4

2x – 3 = (2*6) - 3 = 12-3 = 9

x + 1 = 6 + 1 = 7

Therefore Sides are  4,7  and  9 .

Longest side  = 9

Answer (A)...

JeffTargetTestPrep · Answer

We can create the following equation:

x - 2 + 2x - 3 + x + 1 = 20

4x - 4 = 20

4x = 24

x = 6

The longest side is 2(6) - 3 = 9.

Answer: A

ZahidPavel · Answer

A triangle has sides with lengths x – 2, 2x – 3 and x + 1. If the perimeter of the triangle is 20, what is the length of the longest side?

(A) 9 
(B) 8 
(C) 7
(D) 6 
(E) 5

As we know, x-2+2x-3+x+1 = 20
So, 4x=24, x = 6
the lenght of longest side = 2x-3, that gives us 9
Answer: A

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