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Five friends play blackjack in Las Vegas and lose an average of $100

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Bunuel
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Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink] Five friends play blackjack in Las Vegas and lose an average of $100   07 Nov 2018, 01:09
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Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900
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Re: Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink] Five friends play blackjack in Las Vegas and lose an average of $100   07 Nov 2018, 02:43
Bunuel
Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900


Total lose = 5*100 =500

Lose of 2 friends = 380

Lose of 3 friends = 500 - 380 = 120

Average lose of 3 friends = 120 /3 =40.

The best answer is A.

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Re: Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink] Five friends play blackjack in Las Vegas and lose an average of $100   14 Mar 2019, 07:12
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Bunuel
Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900


The total loss of all the friends is 500 dollars. Since two friends lost 380 dollars, the remaining 3 friends lost a total of 120 dollars, or an average of 120/3 = 40 dollars.

Answer: A
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BrentGMATPrepNow
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Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink] Five friends play blackjack in Las Vegas and lose an average of $100   Updated on: 17 May 2021, 08:31
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Bunuel
Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

Let A, B, C, D and E represent the LOSSES (in dollars) of the 5 friends

Five friends play blackjack in Las Vegas and lose an average of $100 each.
So, we can write: (A+B+C+D+E)/5 = 100
Multiply both sides by 5 to get: A+B+C+D+E = 500

If the losses of two of the friends total $380, what is the average loss of the other friends?
We can write: A+B = 380

Take: A+B+C+D+E = 500 and replace A+B with 380
We get: 380 + (C+D+E) = 500
Subtract 380 from both sides to get: C+D+E = 120

So, the AVERAGE loss of C, D and E (the other friends) = (C+D+E)/3 = 120/3 = 40

Answer: A

Cheers,
Brent

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Originally posted by BrentGMATPrepNow on 15 Jul 2019, 07:46.
Last edited by BrentGMATPrepNow on 17 May 2021, 08:31, edited 1 time in total.
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Re: Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink] Five friends play blackjack in Las Vegas and lose an average of $100   15 Jul 2019, 08:02
Fairly simple,

Total loss of 5 friends = $500

sUBTRACT $380 = $120 /3

$40 is the answer.
Hence A.
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Re: Five friends play blackjack in Las Vegas and lose an average of $100 [#permalink]
15 Jul 2019, 08:02
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