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Bunuel
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Bunuel
Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

Let A, B, C, D and E represent the LOSSES (in dollars) of the 5 friends

Five friends play blackjack in Las Vegas and lose an average of $100 each.
So, we can write: (A+B+C+D+E)/5 = 100
Multiply both sides by 5 to get: A+B+C+D+E = 500

If the losses of two of the friends total $380, what is the average loss of the other friends?
We can write: A+B = 380

Take: A+B+C+D+E = 500 and replace A+B with 380
We get: 380 + (C+D+E) = 500
Subtract 380 from both sides to get: C+D+E = 120

So, the AVERAGE loss of C, D and E (the other friends) = (C+D+E)/3 = 120/3 = 40

Answer: A

Cheers,
Brent

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Fairly simple,

Total loss of 5 friends = $500

sUBTRACT $380 = $120 /3

$40 is the answer.
Hence A.
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