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Math Expert V
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Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 66% (02:04) correct 34% (02:44) wrong based on 193 sessions

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Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Kudos for a correct solution.

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Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Bunuel wrote:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Kudos for a correct solution.

small pizza that measures 10 inches on a side and costs \$10 = 10^2 = 100
large pizza that measures 15 inches on a side and costs \$20 = 15^2 = 225

If they buy pizza alone then the money can buy them each one small and one large = (100+225) = 325 inches each
i.e. Total Size bought be them alone = (325+325) = 650

If they pool their money then they have \$60 so they can buy 3 Large pizza = 3*225 = 675 inches

More = (675-650) = 25 Square inches

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Originally posted by GMATinsight on 01 Jul 2015, 03:18.
Last edited by GMATinsight on 01 Jul 2015, 03:34, edited 1 time in total.
Math Expert V
Joined: 02 Aug 2009
Posts: 7978
Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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GMATinsight wrote:
Bunuel wrote:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Kudos for a correct solution.

small pizza that measures 10 inches on a side and costs \$10
large pizza that measures 15 inches on a side and costs \$20

If they buy pizza alone then the money can buy them each one small and one large = 10+15 = 25 inches each
i.e. Total Size bought be them alone = 25+25 = 50

If they pool their money then they have \$60 so they can buy 4 large pizza = 4*[color=#ff0000]15[/color] = 60 inches

More = 60-50 = 10

hi,
they cannot buy 4 large pizza but only three pizza as the cost is \$20..
also answer is reqd in sq inches not inches
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Math Expert V
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Posts: 7978
Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Bunuel wrote:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Kudos for a correct solution.

area of smaller one = 100 sq inches
area of larger one =15^2=225..
max sq inches that can be bought by them individually =225+100=325 sq inches
total between the two=325*2=650

if the money is collected the best scenario will be buying all large pizzas..
so 225*3=675

so extra=675-650=25
ans D
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Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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In the first case each can buy one pizza of \$10 and one pizza of \$20.

In square inches that would be (10*10=100) for the small pizza and (15*15=225) for the large pizza. In total sq inches that would be (100+225)*2= 650 sq inches.

In the second case if they pool their money together they can buy 3 large pizzas. In terms of square inches that would be 3*225= 675 sq inches.

Hence, the difference is 25 square inches more (675-650).

The correct answer is D.
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Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Small pizza - 10 inches in size - costs \$10.
Large pizza - 15 inches in size - costs \$20.

Case I - when they buy pizzas alone:
A can buy 1 Small and 1 Large, total square inches = (10)^2 + (15)^2 = 100+225 = 325 inch squared.
B can buy 1 Small and 1 Large, total square inches = (10)^2 + (15)^2 = 100+225 = 325 inch squared.

Total inches = 650.

Case II - when they buy together: they can buy one of the following:
(i) 3 Large - 3(15)^2 = 675 inch squared.
(ii) 2 Large + 2 Small = 2(15)^2 + 2(10)^2 = 450 + 200 = 650 inch squared.
(iii) 1 Large + 4 Small = (15)^2 + 4(10)^2 = 225 + 400 = 625 inch squared.

(i) gives the maximum area, so they would get (675-650) = 25 inch squared more. Ans D.
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Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

Solution -

Small pizza size = 100 inch^2 and Large Pizza size = 225 inch^2 -> So buying large pizza gives more cost effective than buying small pizza.

Each friend can buy individually 1 large and 1 small pizza - > 100+225 = 325 inch^2.

So both buy individually 2*325 = 650 inch^2. --------------1

But, both can buy 3 large pizzas combined for \$60 = 3*225 = 675 inch^2. -----------------2

2 - 1 -> Both can get extra pizza = 675-650 = 25 inch^2. ANS D.
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Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Bunuel wrote:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Kudos for a correct solution.

MANHATTAN GMAT OFFICIAL SOLUTION:

First, figure the area of each pizza: the small is 100 square inches, and the large is 225 square inches. If the two friends pool their money, they can buy three large pizzas, which have a total area of 675 square inches. If they buy individually, though, then each friend will have to buy one large pizza and one small pizza, so they will only have a total of 2(100 + 225) = 650 square inches of pizza.

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Re: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that  [#permalink]

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Bunuel wrote:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs \$10, and a large pizza that measures 15 inches on a side and costs \$20. If two friends go to Huey's with \$30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?

A. 5 square inches
B. 10 square inches
C. 15 square inches
D. 25 square inches
E. 350 square inches

Notice it’s a better deal to buy the 15-inch square pizza than the 10-inch square pizza since spending \$20 on a 15^2 = 225 in^2 pizza is better than \$10 on a 10^2 = 100 in^2 pizza (notice that 225/20 > 100/10).

Thus, when they pool their money, with \$60, they should buy three \$20 pizzas.

If they were to not pool their money and buy the pizzas separately, each should buy one \$20 pizza and one \$10 pizza. Thus in total, they should buy two \$20 pizzas and two \$10 pizzas.

Thus, it’s three \$20 pizzas versus two \$20 pizzas and two \$10 pizzas. However, if we take away the two \$20 pizzas from both sides, it’s one \$20 pizza against two \$10 pizzas.

Since one \$20 pizza is 225 in^2 and two \$10 pizzas are 2 x 100 = 200 in^2, pooling the money together buys 225 - 200 = 25 in^2 of extra pizza.

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