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If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 02:15
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88% (01:05) correct 13% (01:18) wrong based on 109 sessions
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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 02:23
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only IMO E If a is divisible by 5! then a must be of the form 120*k when k is an integer 1, 2, 3 then a can be 120, 240, 360, 480.... a/4= 30, 60, 90, 120..... from this we can say a/4 satisfies E.



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If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 02:38
Nice Question. This is a must be true question. Statement 1 => a/4 must be odd Hmm Let a = 5! => clearly a/4 is even> Hence 1 must not be true. Statement 2 => of course it will be true as a must contain a 3 => a/4 must be a multiple of 3 statement 3 => Officourse the least value of a is 5! and 5!/4 is clearly divisibly by 10 Hence E
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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 03:26
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only IMO it is (E) a is divisible by 5*4*3*2 a/4 is divisible by 5*3*2 I is not odd integer hence No II a multiple of 3 Yes III a multiple of 10 Yes
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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 03:35
I getting E.
a/2*3*4*5*4 = a/ 240
so a must be divisible by 3 and 10 but need not necessarily be an odd number



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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 06:43
If a is divisible by 5!, then a/4 must bea = 5*4*3*2*1*K (K = integer) a/4 = 5*3*2*1*K I. an odd integera/4 contains a 2. This cannot be odd. Eliminate. II. a multiple of 3a/4 contains a 3. Is a multiple of 3. Retain. III. a multiple of 10a/4 contains 5 & 2. Retain Answer = E. II and III only
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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 06:57
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only 5! = 120 Now Check the options  I. a/120 can be ODD/EVENa = 240 a/120 = 2 a = 360 a/120 =3 II. Since 5! = 120 a multiple of 3 , any number " a "will be a multiple of 3III. Since 5! = 120 a multiple of 10 , any number " a " will be a multiple of 10 Thus only option (E) is true...
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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 07:14
If a is divisible by 5! ie a is divisible by 2,3,4,5. So a/4 is divisible by 2,3,5.
I) Is it odd integer? No, as it is still divisible by 2 II) Is it multiple of 3? Yes, as it is divisible by 3 III) Is it multiple of 10? Yes, as it is divisible by 2 and 5
So answer is Only II and III ie E



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Re: If a is divisible by 5!, then a/4 must be
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03 Nov 2016, 07:22
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only first of all, 5! = 1*2*3*4*5 a/4 = 1*2*3*5  an even number. I is not true. A and D are out. II  we have a factor of 3, so yes, IT IS a multiple of 3. C is out. III  we have a factor of 2 and a factor of 5  so yes, IT IS a multiple of 10. B is out. the answer is E.



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Re: If a is divisible by 5!, then a/4 must be
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04 Nov 2016, 15:16
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only Since 5! = 5 x 4 x 3 x 2 x 1 = 120, and a is divisible by 5!, we know that a is divisible by some multiple of 120. However since we are determining what MUST be true, we can set a equal to the smallest positive multiple of 120, which is 120. Thus a/4 = 120/4 = 30. Now we can analyze each Roman numeral. I. a/4 is an odd integer Since 120/4 = 30, a/4 does not have to result in an odd integer. Roman numeral one is not correct. II. a/4 is a multiple of 3 Since 120/4 = 30, a/4 will always be a multiple of 3, Roman numeral II is correct. III. a/4 is a multiple of 10 Since 120/4 = 30, a/4 will always be a multiple of 10, Roman numeral III is correct. Answer: E
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Re: If a is divisible by 5!, then a/4 must be
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04 Nov 2016, 21:18
Bunuel wrote: If a is divisible by 5!, then a/4 must be
I. an odd integer II. a multiple of 3 III. a multiple of 10
A. I only B. II only C. III only D. I and III only E. II and III only a is divisible by 5! i.e. a is a multiple of 120 i.e. then a/4 must be a multiple of 120/4 = multiple of 30 Which is Even, a multiple of 3 and a multiple of 10 as well Hence Answer: Option E
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Re: If a is divisible by 5!, then a/4 must be
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03 Dec 2017, 07:22




Re: If a is divisible by 5!, then a/4 must be &nbs
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