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03 Nov 2016, 03:15
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E
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Difficulty:
5%
(low)
Question Stats:
87% (01:00) correct
13%
(01:13)
wrong
based on 119
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If a is divisible by 5!, then a/4 must be
I. an odd integer
II. a multiple of 3
III. a multiple of 10
A. I only
B. II only
C. III only
D. I and III only
E. II and III only
I. an odd integer
II. a multiple of 3
III. a multiple of 10
A. I only
B. II only
C. III only
D. I and III only
E. II and III only
Vinayak Shenoy
Joined: 06 Jun 2016
Last visit: 27 Jun 2017
Posts: 233
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Given Kudos: 212
Location: India
Concentration: Operations, Strategy
Schools: ISB '18 (D)
GMAT 1: 600 Q49 V23
GMAT 2: 680 Q49 V34
GPA: 3.9
03 Nov 2016, 03:23
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Bunuel
If a is divisible by 5!, then a/4 must be
I. an odd integer
II. a multiple of 3
III. a multiple of 10
A. I only
B. II only
C. III only
D. I and III only
E. II and III only
I. an odd integer
II. a multiple of 3
III. a multiple of 10
A. I only
B. II only
C. III only
D. I and III only
E. II and III only
IMO E
If a is divisible by 5! then a must be of the form 120*k when k is an integer 1, 2, 3
then a can be 120, 240, 360, 480....
a/4= 30, 60, 90, 120.....
from this we can say a/4 satisfies E.
stonecold
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03 Nov 2016, 03:38
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Nice Question.
This is a must be true question.
Statement 1 => a/4 must be odd
Hmm Let a = 5! => clearly a/4 is even>
Hence 1 must not be true.
Statement 2 => of course it will be true as a must contain a 3 => a/4 must be a multiple of 3
statement 3 => Officourse the least value of a is 5! and 5!/4 is clearly divisibly by 10
Hence E
This is a must be true question.
Statement 1 => a/4 must be odd
Hmm Let a = 5! => clearly a/4 is even>
Hence 1 must not be true.
Statement 2 => of course it will be true as a must contain a 3 => a/4 must be a multiple of 3
statement 3 => Officourse the least value of a is 5! and 5!/4 is clearly divisibly by 10
Hence E
