dimmak wrote:

If \(m≠0\), is \(m^3>m^2\)?

1) \(m>0\)

2) \(m^2>m\)

1 alone is of course not sufficient because each provides little information.

2 alone will lead to "yes" for positive values such as m=3 and no for negative values such m=-3. Hence. 2 is also insufficient.

It's between C and E.

Combining, if m is positive and m^2 > m which means that m is greater than 1. For all m>1, m^3 > m^2. Hence, yes, m^3 > m^2.

C is the answer.