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555-605 Level|   Number Properties|                  
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Quote:
If m is an integer, is m odd?

(1) m/2 is not an even integer.
(2) m – 3 is an even integer.

This thread sure had some interesting discussion related to St. 1 :)

Here's an alternate, visual, way of processing St. 1:

We'll try to get a visual sense of what St. 1 is conveying.

We know that 'Integers' is a subset within the set of ALL Real Numbers. And, this set of 'Integers' is further divided into two subsets - Even and Odd.

So, if I represent the subset 'Even Integers' with Red color, then the blue zone represents 'Integers that are not Even, that is, Odd Integers'. And the white zone represents 'Non-Integers.'



Now, if you are told that a real number X is not an Even Integer, that only means that X doesn't lie in the Red Zone.

Can X lie in the blue zone? Sure it can.

Can X lie in the white zone? It can.

So, if you are told that some real number is not an even integer, you are only sure about what this integer is NOT. This number can be an odd integer, or it can be a non-integer (in other words, a fraction).

So, when St. 1 tells you that m/2 is not an even integer, two possibilities arise:

Case 1. m/2 is an odd integer
=> m = 2*odd = Even integer

Case 2. m/2 is a non-integer.
That is, m is not completely divisible by 2.
That is, m leaves a non-zero remainder when divided by 2.

Now, the only possible non-zero remainder that results when a number is divided by 2, is 1 (because 0 ≤ Remainder < Divisor)

This means, m = 2q + 1

That is, m = Odd integer.

Thus, from St. 1, we see that m can either be an even integer or an odd integer. So, St. 1 is not sufficient to arrive at a unique answer.


Hope this visual representation helped further cement your understanding of why St. 1 is insufficient. :)

Best Regards

Japinder
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Bunuel
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) --> \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.

(2) m-3 is an even integer --> \(m-odd=even\) --> \(m=even+odd=odd\). Sufficient.

Answer: B.


statement 1 - m/2 is not an even integer, i am a bit confused, what i interpreted is that the outcome of m/2 has to be an integer.

So if you consider the outcome to be an integer, than m will always be even.
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Bunuel
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) --> \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.

(2) m-3 is an even integer --> \(m-odd=even\) --> \(m=even+odd=odd\). Sufficient.

Answer: B.


statement 1 - m/2 is not an even integer, i am a bit confused, what i interpreted is that the outcome of m/2 has to be an integer.

So if you consider the outcome to be an integer, than m will always be even.

Your interpretation is not correct.

For m/2 not to be an even integer m can be even (10) as well as odd (5). (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
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If m is an integer, is m odd?

(1) m/2 is not an even integer.
(2) m – 3 is an even integer.

We are given that m is an integer and we must determine whether it is odd.

Statement One Alone:

m/2 is not an even integer.

The information in statement one is not enough to determine whether m is odd since m can be odd or even. For example, if m = 3 (an odd number), m/2 = 3/2 = 1.5 is not an even integer. On the other hand, if m = 2 (an even number), m/2 = 2/2 = 1 is not an even integer also.

Thus, statement one is not sufficient to determine whether m is odd. We can eliminate answer choices A and D.

Statement Two Alone:

m – 3 is an even integer.

Since m – 3 is an even integer, we can say m – 3 = even. That is, m = even + 3. Since 3 is odd and we know that even + odd = odd, we know that m must be an odd integer.

Statement two is sufficient to answer the question.

The answer is B.
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- In 1st case

m/2 is not an even integer , so if m is divisible by 2 then m has to be even.

How can we test by substituting m=5 ?

Bunuel .. can you please help
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prags1989
- In 1st case

m/2 is not an even integer , so if m is divisible by 2 then m has to be even.

How can we test by substituting m=5 ?

Bunuel .. can you please help

m/2 is not an even integer does not mean that m/2 is necessarily an odd integer, it can be non-integer too.
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Bunuel
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) --> \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.

(2) m-3 is an even integer --> \(m-odd=even\) --> \(m=even+odd=odd\). Sufficient.

Answer: B.

Why isn't '0' not taken into consideration here? 0 is an integer too.
Statement 1 says m/2 is NOT an even integer. Could it mean that m/2 is zero or positive?
The answer is B, I agree. But for clarification, I'd like to know whether '0' is a possible scenario in statement 1.

Thanks in advance!
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Bunuel
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) --> \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.

(2) m-3 is an even integer --> \(m-odd=even\) --> \(m=even+odd=odd\). Sufficient.

Answer: B.

Why isn't '0' not taken into consideration here? 0 is an integer too.
Statement 1 says m/2 is NOT an even integer. Could it mean that m/2 is zero or positive?
The answer is B, I agree. But for clarification, I'd like to know whether '0' is a possible scenario in statement 1.

Thanks in advance!

Yes, m is an integer. More, it's even integer. So, m cannot be 0 in (1) because in this case m/2 = 0/2 = 0 = even, which contradicts the given fact that m/2 is not an even integer.
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Bunuel
If m is an integer, is m odd?

(1) m/2 is not an even integer --> \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) --> \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.

(2) m-3 is an even integer --> \(m-odd=even\) --> \(m=even+odd=odd\). Sufficient.

Answer: B.


statement 1 - m/2 is not an even integer, i am a bit confused, what i interpreted is that the outcome of m/2 has to be an integer.

So if you consider the outcome to be an integer, than m will always be even.

Your interpretation is not correct.

For m/2 not to be an even integer m can be even (10) as well as odd (5). (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
Hello Bunuel
Could you show a scenario where it can not be an integer at all?
Thanks__
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Asad
Bunuel



statement 1 - m/2 is not an even integer, i am a bit confused, what i interpreted is that the outcome of m/2 has to be an integer.

So if you consider the outcome to be an integer, than m will always be even.

Your interpretation is not correct.

For m/2 not to be an even integer m can be even (10) as well as odd (5). (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
Hello Bunuel
Could you show a scenario where it can not be an integer at all?
Thanks__[/quote]

Sure. Say m = 3, then m/2 = 3/2 = 1.5, which is not an even integer, also it's not an integer at all.
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Bunuel


Your interpretation is not correct.

For m/2 not to be an even integer m can be even (10) as well as odd (5). (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
Hello Bunuel
Could you show a scenario where it can not be an integer at all?
Thanks__

Sure. Say m = 3, then m/2 = 3/2 = 1.5, which is not an even integer, also it's not an integer at all.
:) I know it could be the fraction (1.5) too, but i thought that you're going to make a scenario where the result of m/2 is going to be \(undefined\) ( it can not be an integer at all )
Anyway, thanks__
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If m is an integer, is m odd?

(1) \(\frac{m}{2}\) is not an even integer
(2) m-3 is an even integer

(1) m can be Odd or M can be a fraction; Insufficient.

(2) If an Odd number is deducted from a number and the result becomes even the Original number is always ODD. Such as Odd-odd=even. Sufficient.

The answer is \(B\)
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GMATBusters Odd and even only apply to integers, right? If that is the case AND if it was not told to us that m is an integer then from (1) we know that m/2 is not an even integer BUT we cannot say anything about m. That means m could be:

odd integer = 1 --- Yes
even integer 10 --- No
decimal value = 0.4, 0.5, 0.6 --- No

Can the bold face also be considered as an example if we are NOT told that m is an integer?
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If m is not given to be integer.

10/2 = 5 is also not an even integer.

So we can take = 10.

But 1/2 = 0.5 and 0.4 /2 = 0.2 . These are also not even integers.


Infact , u can simply say if m/2 is not even (no info of m being integer)

m/2 not equal 2k, where k is an integer.

Or m is not equal to 4k, where k is an integer. Hence, m is NOT multiple of 4.

Hoozan
GMATBusters Odd and even only apply to integers, right? If that is the case AND if it was not told to us that m is an integer then from (1) we know that m/2 is not an even integer BUT we cannot say anything about m. That means m could be:

odd integer = 1 --- Yes
even integer 10 --- No
decimal value = 0.4, 0.5, 0.6 --- No

Can the bold face also be considered as an example if we are NOT told that m is an integer?

Posted from my mobile device
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GMATBusters
If m is not given to be integer.

10/2 = 5 is also not an even integer.

So we can take = 10.

But 1/2 = 0.5 and 0.4 /2 = 0.2 . These are also not even integers.


Infact , u can simply say if m/2 is not even (no info of m being integer)

m/2 not equal 2k, where k is an integer.

Or m is not equal to 4k, where k is an integer. Hence, m is NOT multiple of 4.

Hoozan
GMATBusters Odd and even only apply to integers, right? If that is the case AND if it was not told to us that m is an integer then from (1) we know that m/2 is not an even integer BUT we cannot say anything about m. That means m could be:

odd integer = 1 --- Yes
even integer 10 --- No
decimal value = 0.4, 0.5, 0.6 --- No

Can the bold face also be considered as an example if we are NOT told that m is an integer?

Posted from my mobile device

Makes sense. Thanks :)
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Only integers can be odd or even, right?

S1 = m/2 is not even doesn't it mean it is odd?

If m/2 is odd that means = m = even.

So, the Answer is no. Hence A is also Sufficient.

Did I miss something?
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