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If x and y are integers with y > 0, is x positive ?
(1) |x| - y = 0
(2) |x - y| > |x + y|
shameekv1989
30 Mar 2020, 01:50
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Bunuel
If x and y are integers with y > 0, is x positive ?
(1) |x| - y = 0
(2) |x - y| > |x + y|
i) y = |x| => y is positive - same as what is given in the question stem - Insufficient
ii) |x - y| > |x + y| => Squaring both sides
\((x-y)^2 > (x+y)^2\) => \(x^2 + y^2 - 2xy = x^2 + y^2 + 2xy\)
\(4xy < 0 \)
Given y > 0 -> x has to be less than 0 i.e. negative
Sufficient
Answer - B
30 Mar 2020, 03:59
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Bunuel
If x and y are integers with y > 0, is x positive ?
(1) |x| - y = 0
(2) |x - y| > |x + y|
Asked: If x and y are integers with y > 0, is x positive ?
(1) |x| - y = 0
|x| = y > 0
x may be +ve or -ve
NOT SUFFICIENT
(2) |x - y| > |x + y|
Since y>0
|y-x| > |y+x|; x must be -ve
SUFFICIENT
IMO B
