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Re: If x is a positive number less than 10, is z greater than the average
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20 Feb 2014, 01:16

9

18

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

Given: \(0<x<10\). Question: is z greater than the average of x and 10? Or: is \(z>\frac{10+x}{2}\)? --> \(2z>10+x\)?

(1) On the number line, z is closer to 10 than it is to x --> \(|10-z|<|z-x|\) --> as z is closer to 10 than it is to x, then z>x, so \(|z-x|=z-x\) --> two cases for 10-z:

A. \(z\leq{10}\) --> \(|10-z|=10-z\) --> \(|10-z|<|z-x|\) becomes: \(10-z<z-x\) --> \(2z>10+x\). Answer to the question YES.

B. \(z>{10}\) --> in this case \(2z>20\) and as \(x<10\), then \(x+10<20\), hence \(2z>10+x\). Answer to the question YES.

OR another approach: Given: x-----average-----10----- (average of x and 10 halfway between x and 10).

Now, as z is closer to 10 than it (z) is to x, then z is either in the blue area, so more than average OR in the green area, so also more than average. Answer to the question YES.

Sufficient.

(2) z = 5x --> is \(2z>10+x\)? --> is \(10x>10+x\)? --> is \(x>\frac{10}{9}\). We don't now that. Not sufficient. (we've gotten that if \(x>\frac{10}{9}\), then the answer to the question is YES, but if \(0<x\leq{\frac{10}{9}}\), then the answer to the question is NO.)

Re: If x is a positive number less than 10, is z greater than the average
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20 Feb 2014, 03:18

7

1

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

(1) On the number line, z is closer to 10 than it is to x. (2) z = 5x

On st1 i'll draw a number line. 0----------------------x-----------------z---10 We can see that z will always be greater than the average. Sufficient

St2 say that z=5x. we'll choose 2 cases: Case 1: x=2, so z=10. avarge is 6 and z is greater than the avarage. Case 2: x=1, so z=5 avarge is 5.5 and z is smaller than the avarage. Insufficient

Re: If x is a positive number less than 10, is z greater than the average
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21 Feb 2014, 03:59

2

Q Is z>(x+10)/2 ; provided that 0<x<10 (1) On the number line, z is closer to 10 than it is to x.

this means distance between z and x is greater than distance between z and 10 on the number line. hence we have z-x>10-z z>(x+10)/2 in the above case z is less than 10 and lies between x and 10. If z is greater 10, then it will definitely be greater than average of x+10. hence z is greater than average of x+10. therefore sufficient.

(2) z = 5x

z=5x assume x=1 average of 10 and 1 = 5.5 and z=5(1) when x=3, average of 10 and 3= 6.5 and z=15

since two different answers are possible hence 2 alone is not sufficient hence correct answer is A

If x is a positive number less than 10, is z greater than the average
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18 May 2015, 06:49

1

1

If x is a positive number less than 10 is z greater than the average of x and 10?

1) on the number line, z is closer to 10 than it is to x

2) z=5x

Drawing a number line can help you see the answer quickly.

Attachment:

Ques2.jpg [ 3.17 KiB | Viewed 3956 times ]

So x is somewhere between 0 and 10 and average of x and 10 is between x and 10. z can be in any of the 5 regions as shown.

1) on the number line, z is closer to 10 than it is to x

In which regions is z closer to 10 than to x? Only the two rightmost regions. There, z is greater than the average of x and 10. Sufficient.

2) z = 5x Put x = 1 z = 5 but average of 1 and 10 is 5.5 so z is less than the average. Actually, this is where I stop and mark (A) as the answer without checking to see if there is a value of x for which z is greater than the average. Think, why?
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Re: If x is a positive number less than 10, is z greater than the average
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13 Dec 2015, 00:13

1

Hi,

i request your help to find out weather statement A is sufficient, when x=8 and Z =9 . Here z is closer to 10 than x, but the average of 10 and X will be equal to z.

Re: If x is a positive number less than 10, is z greater than the average
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13 Sep 2016, 02:50

1

syamukrishnan wrote:

Hi,

i request your help to find out weather statement A is sufficient, when x=8 and Z =9 . Here z is closer to 10 than x, but the average of 10 and X will be equal to z.

Is this correct?

Thanks

No, the Statement 1 says that - Z is closer to 10 than it is to x and not that z is closer to 10 than x is. Your's is the later case.
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Re: If x is a positive number less than 10, is z greater than the average
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05 Oct 2016, 11:25

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Top Contributor

Bunuel wrote:

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

(1) On the number line, z is closer to 10 than it is to x. (2) z = 5x

I received a PM about this question. Here's my solution:

Target question: Is z greater than the mean of x and 10?

Statement 1: On the number line, z is closer to 10 than it is to x. IMPORTANT: On the number line, the mean of two numbers will lie at the midpoint between those two numbers. So, the mean of x and 10 will lie halfway between x and 10. So, if z is closer to 10 than it is to x, then z must lie to the right of the midpoint between x and 10. This means that z must be greater than the mean of x and 10 Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: z = 5x There are several pairs of numbers that meet this condition. Here are two: Case a: x=1, z=5, in which case z is less than the mean of x and 10 (mean = 5.5) Case b: x=4, z=20, in which case z is greater than the mean of x and 10 (mean = 7) Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

(1) On the number line, z is closer to 10 than it is to x. (2) z = 5x

0 < x < 10 Question : is z greater than the average (arithmetic mean) of x and 10?

Question : is z > (x+10)/2? OR Question : is z > Midpoint of x and 10 ?

Statement 1: On the number line, z is closer to 10 than it is to x.

i.e. z is to the right of "midpoint of 10 and x"

i.e. z is GREATER than x

SUFFICIENT

Statement 2: z = 5x

@x = 1, Midpoint = (1+10)/2 = 5.5 and z = 5 i.e. z < AVerage

@x = 2, Midpoint = (2+10)/2 = 6 and z = 10 i.e. z > AVerage

NOT SUFFICIENT

Answer: Option A
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Re: If x is a positive number less than 10, is z greater than the average
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14 May 2019, 09:14

Question: 2z > x+10? Strategy: Plug in values

(1) On the number line, z is closer to 10 than it is to x. If z=10 then 20 > 9.999 + 10 (or whatever x is, it's smaller than 10), YES If x=1 then z > 5.5, like 5.6... so bit more than 11, 11.2 > 1 + 10, YES Sufficient.

(2) z = 5x If x=9 then z=45, 90 > 19, YES If x=1/2 then z=5/2, 5 > 11.5, NO Insufficient.

Re: If x is a positive number less than 10, is z greater than the average
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25 Jun 2019, 14:17

VeritasKarishma wrote:

If x is a positive number less than 10 is z greater than the average of x and 10?

1) on the number line, z is closer to 10 than it is to x

2) z=5x

Drawing a number line can help you see the answer quickly.

Attachment:

Ques2.jpg

So x is somewhere between 0 and 10 and average of x and 10 is between x and 10. z can be in any of the 5 regions as shown.

1) on the number line, z is closer to 10 than it is to x

In which regions is z closer to 10 than to x? Only the two rightmost regions. There, z is greater than the average of x and 10. Sufficient.

2) z = 5x Put x = 1 z = 5 but average of 1 and 10 is 5.5 so z is less than the average. Actually, this is where I stop and mark (A) as the answer without checking to see if there is a value of x for which z is greater than the average. Think, why?

VeritasKarishma From your explanation: Statement 1 says: YES Statement 2 says: NO (before finding YES value) We should not try for finding YES value in statement 2. Without finding YES value in statement 2, we can confidently say that the correct choice is A, because both statements can't contradict each other! Is it the right way to choose A? Thanks__
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If x is a positive number less than 10, is z greater than the average
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25 Jun 2019, 22:18

Asad wrote:

VeritasKarishma wrote:

If x is a positive number less than 10 is z greater than the average of x and 10?

1) on the number line, z is closer to 10 than it is to x

2) z=5x

Drawing a number line can help you see the answer quickly.

Attachment:

Ques2.jpg

So x is somewhere between 0 and 10 and average of x and 10 is between x and 10. z can be in any of the 5 regions as shown.

1) on the number line, z is closer to 10 than it is to x

In which regions is z closer to 10 than to x? Only the two rightmost regions. There, z is greater than the average of x and 10. Sufficient.

2) z = 5x Put x = 1 z = 5 but average of 1 and 10 is 5.5 so z is less than the average. Actually, this is where I stop and mark (A) as the answer without checking to see if there is a value of x for which z is greater than the average. Think, why?

VeritasKarishma From your explanation: Statement 1 says: YES Statement 2 says: NO (before finding YES value) We should not try for finding YES value in statement 2. Without finding YES value in statement 2, we can confidently say that the correct choice is A, because both statements can't contradict each other! Is it the right way to choose A? Thanks__

Yes, absolutely! The two statements won't contradict each other so your answer will be (A). But if I am not running out of time, I will probably get the Yes answer too for stmnt 2, just for my satisfaction!!
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Re: If x is a positive number less than 10, is z greater than the average
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28 Jun 2019, 15:35

Bunuel wrote:

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

Given: \(0<x<10\). Question: is z greater than the average of x and 10? Or: is \(z>\frac{10+x}{2}\)? --> \(2z>10+x\)?

(1) On the number line, z is closer to 10 than it is to x --> \(|10-z|<|z-x|\) --> as z is closer to 10 than it is to x, then z>x, so \(|z-x|=z-x\) --> two cases for 10-z:

A. \(z\leq{10}\) --> \(|10-z|=10-z\) --> \(|10-z|<|z-x|\) becomes: \(10-z<z-x\) --> \(2z>10+x\). Answer to the question YES.

B. \(z>{10}\) --> in this case \(2z>20\) and as \(x<10\), then \(x+10<20\), hence \(2z>10+x\). Answer to the question YES.

OR another approach: Given: x-----average-----10----- (average of x and 10 halfway between x and 10).

Now, as z is closer to 10 than it (z) is to x, then z is either in the blue area, so more than average OR in the green area, so also more than average. Answer to the question YES.

Sufficient.

(2) z = 5x --> is \(2z>10+x\)? --> is \(10x>10+x\)? --> is \(x>\frac{10}{9}\). We don't now that. Not sufficient. (we've gotten that if \(x>\frac{10}{9}\), then the answer to the question is YES, but if \(0<x\leq{\frac{10}{9}}\), then the answer to the question is NO.)

Answer: A.

can we consider x=11 in the highlighted part Bunuel ? Thanks__
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Re: If x is a positive number less than 10, is z greater than the average
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18 Aug 2019, 01:15

hi, can anyone please tell me, what does positive number means (can x takes only integer values or can x takes any value like .1,.2,2.3 etc less than 10)

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10? 0<x<10 Q. z>(x+10)/2?

(1) On the number line, z is closer to 10 than it is to x. x-------------M=(x+10/2)----z----------10 It is evident that x+10/2 = M <z SUFFICIENT

(2) z = 5x Q. 5x > (x + 10)/2 ? Q. 10x > x + 10 ? Q. 9x > 10 ? Q. x > 10/9 ? But x may or may not be >10/9 x may be 1 < 10/9 or x may be 2 > 10/9 NOT SUFFICIENT

IMO A
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