Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
03 Jul 2019, 08:00
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
60% (02:02) correct
40%
(02:17)
wrong
based on 465
sessions
History
Date
Time
Result
Not Attempted Yet
If \(xy > 0\), is \(\frac{y}{x} + \frac{x}{y} > 2\)?
(1) \(y = x - 1\)
(2) \(x = 2y\)
(1) \(y = x - 1\)
(2) \(x = 2y\)
|
firas92
Current Student
Joined: 16 Jan 2019
Last visit: 02 Dec 2024
Posts: 619
Own Kudos:
Given Kudos: 142
Location: India
Concentration: General Management
Schools: Tepper '23 (M$) Foster '23 (D)
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Products:
03 Jul 2019, 08:10
Kudos
Bookmarks
\(\frac{x^2+y^2}{xy}>2\)
Since xy>0, we can multiply the stem by xy maintaining the same inequality and we know that neither x nor y can be 0
So, \(x^2+y^2>2xy\) or \(x^2+y^2-2xy>0\) or \((x-y)^2>0\)
So we need to find whether \((x-y)^2>0\), this will be true when x-y is not equal to 0
(1) \(y=x-1\)
So, \(x-y=1\) => We know that x-y is non zero
So Sufficient
(2) \(x=2y\)
Or, \(x-y=y\)
Since y is non zero, \((x-y)^2 > 0\)
Sufficient
Answer is (D)
Since xy>0, we can multiply the stem by xy maintaining the same inequality and we know that neither x nor y can be 0
So, \(x^2+y^2>2xy\) or \(x^2+y^2-2xy>0\) or \((x-y)^2>0\)
So we need to find whether \((x-y)^2>0\), this will be true when x-y is not equal to 0
(1) \(y=x-1\)
So, \(x-y=1\) => We know that x-y is non zero
So Sufficient
(2) \(x=2y\)
Or, \(x-y=y\)
Since y is non zero, \((x-y)^2 > 0\)
Sufficient
Answer is (D)
General Discussion
03 Jul 2019, 08:14
Kudos
Bookmarks
xy > 0
--> Both x>0 & y>0 (OR) x<0 & y<0
(1) y = x - 1
Since both x & y are of same sign, Irrespective of their values, x/y + y/x will always be > 2
eg: x = 2, y = 1
--> 2/1 + 1/2 = 2.5 > 2
x = 5, y = 4
--> 5/4 + 4/5 = 1.25 + 0.8 = 2.05 > 2
Sufficient
(2) x = 2y
--> x/y = 2
--> x/y + y/x = 2 + 1/2 = 2.5 > 2
Sufficient
IMO Option D
Pls Hit Kudos if you like the solution
--> Both x>0 & y>0 (OR) x<0 & y<0
(1) y = x - 1
Since both x & y are of same sign, Irrespective of their values, x/y + y/x will always be > 2
eg: x = 2, y = 1
--> 2/1 + 1/2 = 2.5 > 2
x = 5, y = 4
--> 5/4 + 4/5 = 1.25 + 0.8 = 2.05 > 2
Sufficient
(2) x = 2y
--> x/y = 2
--> x/y + y/x = 2 + 1/2 = 2.5 > 2
Sufficient
IMO Option D
Pls Hit Kudos if you like the solution
