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If z is an odd integer, is 300z > 1500?
(1) \(0<\sqrt{z}<8\)
(2) \(1<z^2<45\)
(1) \(0<\sqrt{z}<8\)
(2) \(1<z^2<45\)
ENGRTOMBA2018
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07 Nov 2015, 17:02
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Mascarfi
If z is an odd integer, is 300z>1500?
Statement 1, 0<\(\sqrt{z}\)<8
Statement 2, 1<\(z^2\)<45
Statement 1, 0<\(\sqrt{z}\)<8
Statement 2, 1<\(z^2\)<45
Z= odd integer, is 300z>1500 ---> z>5 ?
Statement 1, \(0 < \sqrt{z} < 8\) ---> 1<z<64 so if z=3 or 5, answer is "no" but if z=7,9,11... the answer is "yes". Statement is not sufficient.
Statement 2, \(1<z^2<45\) --> only possible values are z=3 or 5, giving you a "no" . Sufficient.
B is the correct answer.
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jmikery
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08 Nov 2015, 05:32
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300z>1500 is just z>5
Using statement 1, we know that Z is the square of either 1, 3, 5, or 7. Meaning Z can be 1, 9, 25, or 49. Since 1<5 while all the others are >5, INSUFFICIENT.
Using statement 2, we know that Z is the square root of either 9 or 25. Z can then be positive or negative 3 or 5. No matter what the sign, all values of Z are not greater than 5, SUFFICIENT
Using statement 1, we know that Z is the square of either 1, 3, 5, or 7. Meaning Z can be 1, 9, 25, or 49. Since 1<5 while all the others are >5, INSUFFICIENT.
Using statement 2, we know that Z is the square root of either 9 or 25. Z can then be positive or negative 3 or 5. No matter what the sign, all values of Z are not greater than 5, SUFFICIENT
