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In a card game named Allemande, each of four players has a hand of 8 cards from a standard deck of 52. Through a series of discards, players try to maximize the point value of their final hand. Suits are irrelevant. Cards Ace through 10 have a point value of the number of their card: for example, the five of any suit would be worth 5 points. Face cards (Jack, Queen, and King) are worth 20 points each. Does Charles have the highest value final hand?

(1) Charles’ hand is worth 117 points.
(2) No other player besides Charles has more than four face cards in his hand.

We cannot solve the question from individual statements because we do not know either about Charles's hand or about other player's hands.

We should try by combining both the statements together.
No other player has more than 4 face cards.

With 4 face cards, maximum score possible is 4*20 + 4*10 = 120
In this case, we can assume Charles has 5 face cards, 1 nine, 1 seven and 1 ace = 5*20 + 9 + 7 + 1 = 117
So, Charles does not have the maximum.

We can easily form a case where Charles with 117 points has the maximum.

So, even after combining both the statements, we cannot find a unique answer.
Correct Answer: E
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Bunuel
In a card game named Allemande, each of four players has a hand of 8 cards from a standard deck of 52. Through a series of discards, players try to maximize the point value of their final hand. Suits are irrelevant. Cards Ace through 10 have a point value of the number of their card: for example, the five of any suit would be worth 5 points. Face cards (Jack, Queen, and King) are worth 20 points each. Does Charles have the highest value final hand?

(1) Charles’ hand is worth 117 points.
(2) No other player besides Charles has more than four face cards in his hand.


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MAGOOSH OFFICIAL SOLUTION:

Statement #1 is obviously not sufficient, because it only tells us about Charles, and nothing about everyone else.

Statement #2 is obviously not sufficient, because it only tells us about everyone else, and nothing about Charles.

The whole question revolves around what happens with the combined statements.

Charles has 117 points, a strong hand. No one else has more than four face cards. Clearly, most players, say someone with no face cards, would have to be below Charles. We have no doubt that some players are below Charles. Could anyone possibly have more than Charles? Well, suppose one person had four face cards (4*20 = 80 points) and also had all four 10’s in the deck — then, that person would have a total point value of 80 + 10 + 10 + 10 + 10 = 120, higher than Charles. So, given the combined conditions, most people will have less than Charles, but someone could have a hand worth more than Charles’s hand, so even with the combined statements, we cannot say definitively that Charles has the highest value hand. Nothing is sufficient here.

Answer = (E)
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Bunuel
In a card game named Allemande, each of four players has a hand of 8 cards from a standard deck of 52. Through a series of discards, players try to maximize the point value of their final hand. Suits are irrelevant. Cards Ace through 10 have a point value of the number of their card: for example, the five of any suit would be worth 5 points. Face cards (Jack, Queen, and King) are worth 20 points each. Does Charles have the highest value final hand?

(1) Charles’ hand is worth 117 points.
(2) No other player besides Charles has more than four face cards in his hand.


Kudos for a correct solution.

Total points in the deck: 4(1+2+3+4....+10) + (4)(3)(20)
-> 300

Basically, total points in the deck: 300
1st min hand: AAAA 2222 -> 12
2nd min hand: 3333 4444 -> 28
Total: 40

-> 3rd and Charles will share: 260 among them.

1)
Charles has 117
Then 3rd has: 143
So MAX: 143 MIN: 12
Since there are hands better than 117 and also some hands worse than 117, it can't be definitely said that Charles has the best hand -> INSUFF

2) MIN is the same: 12
MAX is now: 20x4 + 10x4 (FFFF 10,10,10,10)
-> 120
Again: Charles does not have a better hand, for certain. Could be, could be not. -> INSUFF

Combine)
MIN: 12
MAX: 120
117 is in between. Y or N, -> INSUFF
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Straight E.
1. Insufficient as the max value can go up to 160 and that too two players can have 160 each insufficient
2. This statement gives us no definite answer as different combinations yield both a higher value and a lower value than Charles points-insufficient
3. 20x+10y can yield both a lesser value and higher than 117 insufficient
Hence E


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