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19 Aug 2019, 01:03
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\(m=\frac{\frac{3}{n}}{\frac{2}{y}+\frac{1}{2y}}\)
In the expression above, if yn ≠ 0, what is the value of m?
(1) y = 3n/2
(2) n = 3/2
In the expression above, if yn ≠ 0, what is the value of m?
(1) y = 3n/2
(2) n = 3/2
19 Aug 2019, 01:03
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Bunuel
\(m=\frac{\frac{3}{n}}{\frac{2}{y}+\frac{1}{2y}}\)
In the expression above, if yn ≠ 0, what is the value of m?
(1) y = 3n/2
(2) n = 3/2
In the expression above, if yn ≠ 0, what is the value of m?
(1) y = 3n/2
(2) n = 3/2
Similar question from OG: https://gmatclub.com/forum/in-the-expre ... 44341.html
Updated on: 19 Aug 2019, 03:50
Originally posted by garcmillan on 19 Aug 2019, 03:49.
Last edited by garcmillan on 19 Aug 2019, 03:50, edited 1 time in total.
Last edited by garcmillan on 19 Aug 2019, 03:50, edited 1 time in total.
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The most important thing to realize in this question is that it is asking by the value of m, so we need to cancel both y and n so that the given option is SUFFICIENT.
1) y = 3n/2 ---> Let's substitute y by 3n/2 in the given equation:
m=(3/n)/(2/y+1/12y) --->(3/n)/(4/3n+2/36n) ---> (you can keep simplyfing this formula from here, but before doing that you just need to realize that in the numerator we have a fraction with n in the denominator and in the denominator we have a fraction with n in the denominator. That means that regardless of the numbers that the equation will have, at the end, n wil be cancelled ---> SUFFICIENTE
2) n = 3/2 ---> Don't even start substituting because we have no info about y so m will depend on y ---> NO SUFFICIENT
OPTION A
Note that it is very important in DS problems to save most of the time by not doing extra steps. You should quickly relaize in option 1 that n would cancel
Please hit the kudos button if this post helped you
1) y = 3n/2 ---> Let's substitute y by 3n/2 in the given equation:
m=(3/n)/(2/y+1/12y) --->(3/n)/(4/3n+2/36n) ---> (you can keep simplyfing this formula from here, but before doing that you just need to realize that in the numerator we have a fraction with n in the denominator and in the denominator we have a fraction with n in the denominator. That means that regardless of the numbers that the equation will have, at the end, n wil be cancelled ---> SUFFICIENTE
2) n = 3/2 ---> Don't even start substituting because we have no info about y so m will depend on y ---> NO SUFFICIENT
OPTION A
Note that it is very important in DS problems to save most of the time by not doing extra steps. You should quickly relaize in option 1 that n would cancel
Please hit the kudos button if this post helped you
