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Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28

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Bunuel
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Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink] New post   27 Feb 2018, 21:16
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D
E

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Is x > 9?

(1) x^2 + 3x = 28
(2) 9x = 5x − 28
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D
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gmatexam439
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Re: Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink] New post   27 Feb 2018, 21:52
Bunuel wrote:
Is x > 9?

(1) x^2 + 3x = 28
(2) 9x = 5x − 28


Statement 1:
(x+7)(x-4)=0
x=-7 / 4 --Sufficient

Statement 2:
4x=-28
x=-7 --Sufficient

IMO answer should be "D"
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Re: Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink] New post   27 Feb 2018, 22:06
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Bunuel wrote:
Is x > 9?

(1) x^2 + 3x = 28
(2) 9x = 5x − 28


Is x> 9

1)
x^2 + 3x = 28
x^2+3x-28 = 0
x^2+7x-4x-28=0
(x+7)(x-4)=0
x = -7 or 4
Both the values of x less than 9, hence statement 1 is sufficient.

2)
9x = 5x - 28
4x = -28
x = -7
-7 < 9, Hence statement 2 is sufficient.

Option D should be the answer.
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chandan1988
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Re: Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink] New post   27 Feb 2018, 23:24
Bunuel wrote:
Is x > 9?

(1) x^2 + 3x = 28
(2) 9x = 5x − 28

Statement 1:
x^2+3x-28=0
Solving the quadratic eqn
X=4,-7
Both are less than 9
Sufficient

Statement 2:
9x=5x-28
4x=-28
X=-7
Sufficient

Ans: D

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Re: Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink] New post   11 Feb 2020, 13:08
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Re: Is x > 9? (1) x^2 + 3x = 28 (2) 9x = 5x − 28 [#permalink]
11 Feb 2020, 13:08
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