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Liqueur A contains 24% of alcohol. What is the alcohol concentration

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Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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08 Jul 2016, 07:09
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Liqueur A contains 24% of alcohol. What is the alcohol concentration of the mixed cocktail of liqueur A and B?

(1) The mixing ratio of liqueur A and B is 1:4
(2) The alcohol concentration of liqueur B is 1.5 times greater than the alcohol concentration of the mixed cocktail.

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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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08 Jul 2016, 10:15
Percentage of alcohol in Liqueur A = 24
alcohol concentration of the mixed cocktail of liqueur A and B ?

(1) The mixing ratio of liqueur A and B is 1:4
Not sufficient as we have no information about alcohol % in liqueur B
(2) The alcohol concentration of liqueur B is 1.5 times greater than the alcohol concentration of the mixed cocktail
Percentage of alcohol in Liqueur B= 24 + 1.5*24 = 60
Not sufficient as we do not know ratio of A and B in the cocktail .
Combining 1 and 2 , we get
Sufficient

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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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16 Jul 2016, 20:17
Skywalker18 wrote:
Percentage of alcohol in Liqueur A = 24
alcohol concentration of the mixed cocktail of liqueur A and B ?

(1) The mixing ratio of liqueur A and B is 1:4
Not sufficient as we have no information about alcohol % in liqueur B
(2) The alcohol concentration of liqueur B is 1.5 times greater than the alcohol concentration of the mixed cocktail
Percentage of alcohol in Liqueur B= 24 + 1.5*24 = 60
Not sufficient as we do not know ratio of A and B in the cocktail .
Combining 1 and 2 , we get
Sufficient

but "24" is alcohol concentration of Liquor A not Mixed cocktail..so how we determine % of alcohol in liquor B= 24+1.5*24
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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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16 Jul 2016, 21:22
Concentration of Alcohol in A = 24%
Concentration of Alcohol in B = B%
Concentration of Alcohol in the mixed solution = M%

St1: Mixing Ratio of A and B = 1:4 = x : 4x
Not Sufficient to calculate the concentration of Alcohol in the mixed solution as we can have a number of different values for x.

St2: B = 2.5*M --> Clearly insufficient as we have two unknowns

Combine St1 and St2: Using the allegation technique we have,
24 - 4x = M
M - B = x --> M = x + B
24 - 4x = x + B
24 - 5x = 2.5(24 - 4x)
We can find the value of x and determine the value of M.
Sufficient

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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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21 Aug 2016, 03:44
Bunuel can you please explain this?
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Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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12 Oct 2016, 04:05
Bunuel

Can you pls explain this.

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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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13 Nov 2016, 09:40
Bunuel wrote:
Liqueur A contains 24% of alcohol. What is the alcohol concentration of the mixed cocktail of liqueur A and B?

(1) The mixing ratio of liqueur A and B is 1:4
(2) The alcohol concentration of liqueur B is 1.5 times greater than the alcohol concentration of the mixed cocktail.

weighted average DS

wa/wb= Ab-weighted average of mix / weighted average -0.24

what is WEIGHTED AVERAGE?? we need wa,wb,Ab,

from 1

wa:wb = 1:4 ... insuff

from 2

Weighted average = 2/3 wb.. insuff

both we have wa:wb and we have wb in terms of weighted average ( equation has one unknown now) .....C
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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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16 Nov 2016, 09:37
didn't get it... pls explain..?
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Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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16 Nov 2016, 21:45
1
VIJAYTHAPLIYAL wrote:
didn't get it... pls explain..?

I am using a weighted average formula , Since the question is asking for a final concentration of a mix that is the same as asking for the weighted average of the 2 solutions concentration of alcohol.

Weight A concentration of alcohol in B - Weighted average of the final mix
--------- = ------------------------------------------------------
weight B Weighted average of the final mix - Concentration of alcohol in A (given as 24%)

Question asks for the weighted average of alcohol concentration in the final mix? thus we need Weight A, Weight B , Concentration of alcohol in B

FROM 1

Weight A 1
--------- = --- We still need concentration of alcohol in B......... INSUFF
weight of B 4

FROM 2

Concentration in B = 1.5 *0.24............. INSUFF since we need Weight A and Weight B

Both together

we have all 3 missing unknowns to solve the equation.........thus suff

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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration  [#permalink]

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06 Sep 2018, 17:22
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Re: Liqueur A contains 24% of alcohol. What is the alcohol concentration   [#permalink] 06 Sep 2018, 17:22
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