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Of the 66 people in a certain auditorium, at most 6 people
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16 Jul 2012, 04:49
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55% (01:34) correct 45% (01:44) wrong based on 1322 sessions
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Of the 66 people in a certain auditorium, at most 6 people have their birthdays in anyone given month. Does at least one person in the auditorium have a birthday in January? (1) More of the people in the auditorium have their birthday in February than in March. (2) Five of the people in the auditorium have their birthday in March. Diagnostic Test Question: 45 Page: 26 Difficulty: 650
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Re: Of the 66 people in a certain auditorium, at most 6 people
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16 Jul 2012, 13:08
SOLUTIONOf the 66 people in a certain auditorium, at most 6 people have their birthdays in anyone given month. Does at least one person in the auditorium have a birthday in January?Basically the question is whether we can distribute 66 birthdays between 12 moths so that January to get 0. (1) More of the people in the auditorium have their birthday in February than in March. Let 10 months (except March and January) have 6 birthdays each (maximum possible) > 6*10=60. As in March there was less birthdays than in February than maximum possible for March is 5 > total 60+5=65, so even for the worst case scenario (maximum for other months) still 1 birthday (6665=1) is left for January. Sufficient. (2) Five of the people in the auditorium have their birthday in March. Again: let 10 months have 6 birthdays each (maximum possible) > 6*10=60 + 5 birthdays in March = 65. The same here: even for the worst case scenario (maximum for other months) still 1 birthday (6665=1) is left for January. Sufficient. Answer: D. Hope it helps.
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Re: Of the 66 people in a certain auditorium, at most 6 people
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16 Jul 2012, 19:43
Assume that January has 0 birthdays => all other months have 6 birthdays to total 66.
Statement 1: "More of the people in the auditorium have their birthday in February than in March" => March needs to be less than February, say March has 5 so that March (5) < February (6). The one birthday which has been 'plucked' from March, can only be accommodated in January since all other months are maxed out. => Jan has atleast one. Sufficient.
Statement 2: "Five of the people in the auditorium have their birthday in March"  same logic as for statement 1. Sufficient.
Answer: (D)



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Re: Of the 66 people in a certain auditorium, at most 6 people
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16 Jul 2012, 19:46
Q is does any one have their b'day in jan
given: max people(with their b'day) in any given month is 6. no of people is 66 .
stmt 1 : no of people in feb > no of people in march
lets consider the number of b'day people in feb as 6 (max) so no of people in march cud be 5 or 4 or 3 or 2 or 1 or 0 . now max total is (6 in feb) + (5 in march) = 11 (6611=55) other remaining months from april to december can hold max 6 people each which means 6 * 9 = 54 people covered. and only one person remaining out of 55 who fits into jan. therby atleast 1 person's b'day is in jan.
sufficient
stmt 2 : no of people having bday in march is 5
so 665 = 61. no of months other than march and jan is 10 . so considering each months holds max of 6 . (10 * 6 = 60) remaining 1 left who cud be in jan.
sufficient
IMO D



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Re: Of the 66 people in a certain auditorium, at most 6 people
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17 Jul 2012, 02:52
lateapp wrote: Assume that January has 0 birthdays => all other months have 6 birthdays to total 66.
Statement 1: "More of the people in the auditorium have their birthday in February than in March" => March needs to be less than February, say March has 5 so that March (5) < February (6). The one birthday which has been 'plucked' from March, can only be accommodated in January since all other months are maxed out. => Jan has atleast one. Sufficient.
Statement 2: "Five of the people in the auditorium have their birthday in March"  same logic as for statement 1. Sufficient.
Answer: (D) Agreed. In order for for there to be no January birthdays, FebDec must each have 6. Statements to the contrary answer the question.



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Re: Of the 66 people in a certain auditorium, at most 6 people
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18 Jul 2012, 00:41
Any month can have a max of 6 people celebrating their birthdays. No information is given about the min people or a lower cap of people.
(1)Feb>Mar implies that it can be a combination of any of the following. Feb,Mar : 1,0 ; 2,0 ; 2,1 ; 3,0 ; 3,1 ; 3,2 and so on. No information is given about the other 10 months. We cannot simply populate the values for the other 10 months with just the cap for the maximum number of birthdays.(Although a minimum number would have been useful in this regard)
NOT SUFFICIENT
(2)5 people have their birthdays in March. This does not give any information about the other months. Combining with the information given in the question, we can say that the condition has not been violated.
NOT SUFFICIENT
(1&2) Imply that Feb has 6 birthdays. Still we do not have information about the other months. 66(6+5) = 55 member can have their birthdays distributed in 10 months in any number of ways as long as any of the remaining months do not exceed 6 birthdays. No information on the number of birthdays in Jan.
NOT SUFFICIENT
Hence 'E' must be the solution.



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Re: Of the 66 people in a certain auditorium, at most 6 people
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09 Jan 2014, 11:14
The question really asks us if there is a month  except january  where less than 6 people have their birthday.
Both statements alone tell us the answer to this is "yes", and both more or less tell us the same thing, actually.



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Re: Of the 66 people in a certain auditorium, at most 6 people
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14 Jun 2016, 22:20
After reading the prompt,I realized that in order to satisfy the condition that the 'NO' answer to the DS question requires that each month we have 6 people having their birthdays. Why? Because again the prompt says that we have 66 people and in a month we cant have more than 6 people's birthdays. So if Jan =0 then 0,6,6,6,6,6,6,6,6,6,6,6 If we violate the possibility of 0,6,6,6,6,6,6,... then we get a firm answer of YES to the DS.
Statement #1  says that Feb and March are unequal. So obviously they cant be equal. and hence the answer is YES.sufficient statement #25 have birthdays in March. Again we violate the possibility of 0,6,6,6,6,...... So again we get a firm answer YES. sufficient



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Re: Of the 66 people in a certain auditorium, at most 6 people
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04 Aug 2018, 22:35
Is this really a 650 difficulty word problem question?



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Re: Of the 66 people in a certain auditorium, at most 6 people
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05 Aug 2018, 04:32
philipssonicare wrote: Is this really a 650 difficulty word problem question? The difficulty level of a question is calculated automatically based on the timer stats from the users which attempted the question. So our stats say that it's 700 level.
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Re: Of the 66 people in a certain auditorium, at most 6 people
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05 Oct 2018, 07:53
Hi Bunuel, Are there similar problems like these? Could you please share the link?
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Of the 66 people in a certain auditorium, at most 6 people
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Updated on: 19 Aug 2019, 02:37
This question needs some logic + inference based thinking. If you get that part right, the sum becomes very easy
Soln  Lets assume every month had 6 birthdays, so 12 * 6 = 72 (Note that we have 66 people and we are getting 72 i.e. 6 extra people) . So we can have a situation in which FebDec have 6 people and Jan has none. (11 months have 6 people = 11*6 = 66 people) . Inference  Even if 1 month has less than 6 then Jan WILL have at least 1 . . Each statement alone conveys that 1 month has less than 6 people i.e Jan WILL have at least 1 . . (D)
Originally posted by Hoozan on 19 Aug 2019, 01:52.
Last edited by Hoozan on 19 Aug 2019, 02:37, edited 1 time in total.



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Re: Of the 66 people in a certain auditorium, at most 6 people
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19 Aug 2019, 02:31
Bunuel wrote: Of the 66 people in a certain auditorium, at most 6 people have their birthdays in anyone given month. Does at least one person in the auditorium have a birthday in January? (1) More of the people in the auditorium have their birthday in February than in March. (2) Five of the people in the auditorium have their birthday in March. Diagnostic Test Question: 45 Page: 26 Difficulty: 650 Only scenario when there can be no birthday in January is that in all other months there should be 6 birhtdays ( which is maximum for any given month as per question). 1  This means Feb and March have different figure and not both as 6. Which means there has to be atleast 1 birthday in Jan. Best case scenario  Let birthday in Feb be 6 and in March it cannot be 6 so let it be 5. To get the least no. of birthday in Jan, let in all other months the no. of birthday be 6. So, total no. of birthdays excluding Jan would be = 6x10 (for 10 months excluding Jan and Mar) + 5 (for March) = 65. So the 66th person's bday has to fall in Jan. This is sufficient. 2  If 5 have birthday in March which makes it less than 6 which is required for 0 bday in Jan. Now if we take the maximum for all the other months, it will be 6x10 = 60. So, in all it will be 60+5 (in march) = 65. So, the 66th bday has to fall in Jan. This is also sufficient. Each statement alone is sufficient to answer the question. Hence D.




Re: Of the 66 people in a certain auditorium, at most 6 people
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