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# On line segment AD above, AB = BC = CD. If BD = 36, then AB =

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Joined: 02 Sep 2009
Posts: 54376
On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 01:53
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Difficulty:

15% (low)

Question Stats:

87% (00:28) correct 13% (00:08) wrong based on 39 sessions

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On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:

2017-07-12_1252.png [ 3.03 KiB | Viewed 1021 times ]

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On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 02:14
Bunuel wrote:

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

It should be D.

If 36 is split into 3 equal segments and 2 of those segments are equal to 3, then total length can be calculated by

$$x*2/3 = 36$$

$$x = 36*3/2$$

$$x = 54$$

Then, one of the segments would be $$54/3$$ or $$18$$.
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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 02:25
Since BC = CD and BC + CD = BD = 36.

Let BC = CD = x
2x = 36, or x=18.
Therefore, BD = 36.

Both BC and CD are 18.
Now, since AB = BC = CD, we can also say that AB = 18(Option D)
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On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 04:57
Bunuel wrote:

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

Somewhat basic, but comes in handy on harder problems: To calculate distance between marks, use upper - lower/ # of intervals.

Upper(D) - lower(B) is given: 36. There are two equal intervals between them. 36/2 = 18, so distance between marks is 18.

AB is one interval. AB = 18.

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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 05:03
If BD=36
Then BC=AB=CD=18
D

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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 05:24
Bunuel wrote:

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

AB = BC = CD
BD = 36
So BC = CD = 36/2
AB = BC = CD = 18

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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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12 Jul 2017, 08:33
Bunuel wrote:

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

Let $$AB = BC = CD = x$$

Given, $$BD = 36$$

$$BD = BC + CD = x + x = 2x$$

$$2x = 36$$

$$x = \frac{36}{2} = 18$$

$$AB = 18$$

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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =  [#permalink]

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16 Jul 2017, 17:20
Bunuel wrote:

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

We can let AB = BC = CD = x. Thus, since BD = 36, we have:

2x = 36

x = 18 = AB

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Re: On line segment AD above, AB = BC = CD. If BD = 36, then AB =   [#permalink] 16 Jul 2017, 17:20
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# On line segment AD above, AB = BC = CD. If BD = 36, then AB =

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