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Bunuel

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png
Somewhat basic, but comes in handy on harder problems: To calculate distance between marks, use upper - lower/ # of intervals.

Upper(D) - lower(B) is given: 36. There are two equal intervals between them. 36/2 = 18, so distance between marks is 18.

AB is one interval. AB = 18.

Answer D
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If BD=36
Then BC=AB=CD=18
D

Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
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Bunuel

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

AB = BC = CD
BD = 36
So BC = CD = 36/2
AB = BC = CD = 18

Answer D
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Bunuel

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

Attachment:
2017-07-12_1252.png

Let \(AB = BC = CD = x\)

Given, \(BD = 36\)

\(BD = BC + CD = x + x = 2x\)

\(2x = 36\)

\(x = \frac{36}{2} = 18\)

\(AB = 18\)

Answer (D)...
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Bunuel

On line segment AD above, AB = BC = CD. If BD = 36, then AB =

(A) 9
(B) 12
(C) 16
(D) 18
(E) 27

We can let AB = BC = CD = x. Thus, since BD = 36, we have:

2x = 36

x = 18 = AB

Answer: D
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