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Total work to be done is LCM(2,3) = 6 units.
A can do 3 units in 1 hour.
B can do 2 units in 1 hour.
Together they can do 5 units in 1 hour.
They require 6/5 hours to fill the tank completely.
To fill 2/3 of the tank, they require 2/3*6/5*60 min = 48 min.

B is the answer.
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IMO B .

together they can fill full tank in 6/5 hours = 72 mins .

so 2/3 tank will fill in 72*2/3 = 48 mins

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Considering x as the capacity of the tank

Flow rate of pipe A per minute: \(\frac{x}{(3*60)}=\frac{x}{180}\)

Flow rate of pipe B per minute: \(\frac{x}{(2*60)}=\frac{x}{120}\)

Flow rate of both pipes working together:

\(\frac{x}{120}+\frac{x}{180}=\frac{5x}{360}=\frac{x}{72}\)

\(\frac{x}{72}*t=\frac{2*x}{3}\)

\(t=48min\)

Ans B
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Bunuel
Pipe A can fill a tank in 3 hours. If pipe B can fill the same tank in 2 hours, how many minutes will it take both pipes to fill \(\frac{2}{3}\) of the tank?

A. 30

B. 48

C. 54

D. 60

E. 72

combined rate = 1/3+1/2 = 5/6
so for 2/3 filling
2/3 = 5/6 * time * 1/60
so
time = 2*6*60/3*5 = 48
IMO B
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I think question is edited now. Because previously 2/3rd was written as 2323.
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Bunuel
Pipe A can fill a tank in 3 hours. If pipe B can fill the same tank in 2 hours, how many minutes will it take both pipes to fill \(\frac{2}{3}\) of the tank?

A. 30

B. 48

C. 54

D. 60

E. 72

The rate of pipe A is 1/3, and the rate of pipe B is 1/2. We let n = the time that the two pipes work together to fill 2/3 of the tank and create the equation:

(1/3)n + (1/2)n = 2/3

Multiplying by 6, we have:

2n + 3n = 4

5n = 4

n = 4/5 hour = 48 minutes

Answer: B
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Hello from the GMAT Club BumpBot!

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