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Math Expert V
Joined: 02 Sep 2009
Posts: 58465
The average (arithmetic mean) weight of two men is x, which is twice  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 68% (01:26) correct 32% (01:22) wrong based on 25 sessions

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The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. Which of the following expresses the average weight of all five men in terms of x?

A. x/2
B. 3x/5
C. 7x/2
D. 7x/10
E. 8x/5

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Senior Manager  P
Joined: 16 Jan 2019
Posts: 489
Location: India
Concentration: General Management
WE: Sales (Other)
Re: The average (arithmetic mean) weight of two men is x, which is twice  [#permalink]

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Let the five men be A, B, C, D & E

Average of A & B = x
Average of B, C and D = x/2

Sum of weights of A and B = 2x
Sum of weights of B, C and D = 3x/2

Sum of weights of A, B, C, D and E = 2x+3x/2=7x/2

Average weight of A, B, C, D and E = 7x/2/5 = 7x/10

SVP  P
Joined: 03 Jun 2019
Posts: 1756
Location: India
Re: The average (arithmetic mean) weight of two men is x, which is twice  [#permalink]

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Bunuel wrote:
The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. Which of the following expresses the average weight of all five men in terms of x?

A. x/2
B. 3x/5
C. 7x/2
D. 7x/10
E. 8x/5

Total weight of 5 men = 2x + 3(x/2) = 3.5x

Average weight of 5 men = 3.5x/5 = 7x/10

IMO D
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Director  D
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Concentration: Entrepreneurship, Marketing
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Re: The average (arithmetic mean) weight of two men is x, which is twice  [#permalink]

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Bunuel wrote:
The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. Which of the following expresses the average weight of all five men in terms of x?

A. x/2
B. 3x/5
C. 7x/2
D. 7x/10
E. 8x/5

Let the weights of men be a, b, c, d and e respectively

Average weight of 2 men = x
--> (a + b)/2 = x
--> a + b = 2x ....... (1)

Given x is twice the average weight of three different men
--> x = 2(c + d + e)/3
--> c + d + e = 3x/2 ....... (2)

Average weight of 5 men = (a + b + c + d + e)/5 = (2x + 1.5x)/5 = 3.5x/5 = 7x/10

IMO Option D Re: The average (arithmetic mean) weight of two men is x, which is twice   [#permalink] 16 Oct 2019, 23:57
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